Circumference help what is the approximately circumference of the circle

Suppose you want to count the number of four-letter passwords that can be formed using the letters in the word NUMBER. The four

WITCHER [35]

Answer:

D.The password must not follow order matter

Step-by-step explanation:

We are given that suppose you want to count the number of four letters password that can be formed using the letters in the word NUMBER.

We are given that all letters in the password must be all different .There is no nothing saying about order so we can make combination without order .

We have to find the number of 4- letter password that can be formed using letters in the word NUMBER.

By using Permutation formula we find the number of 4- letters password that can be formed by using the letters N,M,B,U,E,R.

Permutation formula : The number of arrangements when taken r objects at a time out of n objects

= $\frac{n!}{(n-r)!}$

Total letters in word NUMBER=N,U,M,B,E,R=6

n=6,r=4

Therefore, the number of arrangements can be made from 6 letters when 4 letters taken at a time = $\frac{6!}{(6-4)!}$

The number of selection can be made from 6 letters when 4 letters taken at a time = $\frac{6!}{(6-4)!}$

The number of selection can be made from 6 letters when 4 letters taken at a time = $\frac{6\times5\times 4\times3 \times 2!}{ 2!}$

$n!=n(n-1)(n-2)(n-3)...........3\cdot.2\cdot.1$

The number of selection can be made from 6 letters when 4 letters taken at a time =360

Option D is correct.

Answer : D.The password must not follow order matter

6 0

4 years ago

Find f'(x) for f(x) = 5x2 − 3x + 12. 10x + 12(this answer is incorrect) −10x − 3 10x − 3 None of these

nexus9112 [7]

What are ya sayin

Step-by-step explanation:

5 0

3 years ago

23. If XY = 13, XA = 4, and XZ = 26, then XB =

UkoKoshka [18]

Answer:

It is given that in triangle XYZ, XY = 13, YZ=20, and XZ=25.Using the law of cosines, we have

CosC=\frac{a^2+b^2-c^2}{2ab}

cosZ=\frac{(YZ)^2+(XZ)^2-(XY)^2}{2(YZ)(XZ)}

CosZ=\frac{(20)^2+(25)^2-(13)^2}{2(20)(25)}

CosZ=\frac{400+625-169}{1000}

CosZ=\frac{856}{1000}

CosZ=0.856

Z=cos^{-1}(0.856)

Z=37.13^{\circ}

Step-by-step explanation:

5 0

4 years ago

Guys!What will be the right answer of X=?<br>Please explain with picture!

Svetradugi [14.3K]

Answer:6

Step-by-step explanation:

With the 3 on the side we can estimate it being at least half of x so 3(2) , equals 6 hope it helped :)

6 0

3 years ago

A rectangular garden measures 29 ft by 37 ft. surrounding (and bordering) the garden is a path 2 ft wide . find the area of this

Andreas93 [3]

Answer: The area of the path is 280 ft^2

(Note that 280 ft^2 means “280 feet squared”)

Step-by-step explanation: The first clue in this question is the dimensions of the rectangular garden which have been given as 29 ft by 37 ft. So we can conveniently compute the area of the garden as follows;

Area = L x W

(Length is 37 ft and Width is 29 ft)

Area = 37 x 29

Area = 1037 ft^2

However there is a path surrounding the garden which is 2 ft wide on all four sides. This means both borders of the length have an extra 4 feet of measurement while both borders of the width also have an extra 4 feet of measurement. So, if the surrounding border and garden is measured altogether, the length would become (37 + 4= 41) 41 feet while the width would become (29 + 4 = 33) 33 feet. So the area of the garden and the surrounding path inclusive can be calculated as

Area = L x W

Area = 41 x 33

Area = 1353 ft^2

To determine the area of ONLY THE SURROUNDING PATH, we simply deduct the area of the GARDEN ONLY (1073 ft^2) from the area of GARDEN AND SURROUNDING PATH (1353 ft^2)

Therefore area of the path surrounding the garden becomes

Area of path = 1353 - 1073

Area of path = 280 ft^2

7 0

4 years ago