This is a problem of guess and check; there's no easier way to do it.But in this case you must have an odd number of nickels to make the 5 cents, so your answer is 9 nickels.you can check this by multiplying each one by .05:
9*.05=.45
the rest of the coins left, are 8 of them, and their dimes.
.10*8=.80
.80+.45= 1.25
82% of 100 = 82%
Depends on what you’re asking 82% of but usually it would be of 100.. hope this helps
Answer:
increase
Step-by-step explanation:
- Given data is: 71, 67, 67, 17, 69, 84, 21, 87
- Arranging in ascending order we find: 17, 21, 67, 67, 69, 71, 84, 87
- 4th term = 67, 5th term = 69
- -> median = Sum of 4th and 5th term/2 = (67 + 69)/2 = 132/2 = 66
- Now, when one of the 67 is replaced by 71, the new data set in ascending order will be: 17, 21, 67, 69, 71, 71, 84, 87
- Here, 4th term = 69, 5th term = 71
- New median = (69 + 71)/2 = 140/2 = 70
- -> new median > initial median
CONCLUSION: Median will increase if the number 71 replaced one of the 67's in the set.
Hi there! So the the new price is $93, and went up from $55. Let's subtract the numbers. 93 - 55 is 38. The change is 38. To find the percent markup, we can write and solve a proportion. Set it up like this:
38/55 = x/100
This is because the amount of change goes above the original (55), and x represents the percent out of 100. We are looking for the markup. Let's cross multiply the values. 100 * 38 is 3,800. 55 * x is 55x. 3,800 = 55x. Now, divide each side by 55 to isolate the x. 55x/55 cancels out. 3,800/55 is 69.0909 or 69 when rounded to the nearest whole number. There. The percent of markup is approx. 69%.
Answer:
c
Step-by-step explanation:
<em>To </em><em>find </em><em>the </em><em>midpoint</em><em> </em><em>the </em><em>formulas</em>
<em>x=</em><em>x1+</em><em>x2/</em><em>2</em><em> </em><em>and </em><em>y</em><em>=</em><em>y1+</em><em>y2/</em><em>2</em><em> </em><em>are </em><em>used </em>
<em>in </em><em>this </em><em>case </em><em>x1 </em><em>is </em><em>5</em><em>,</em><em>x2 </em><em>is </em><em>5</em><em>,</em><em>y1 </em><em>is </em><em>4</em><em> </em><em>and </em><em>y2 </em><em>is </em><em>-</em><em>3</em>
<em>therefore</em>
<em>x=</em><em>5</em><em>+</em><em>5</em><em>/</em><em>2</em><em>. </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>
<em> </em><em> </em><em>=</em><em>1</em><em>0</em><em>/</em><em>2</em>
<em> </em><em> </em><em>=</em><em>5</em>
<em>y=</em><em>4</em><em>+</em><em>(</em><em>-</em><em>3</em><em>)</em><em>/</em><em>2</em>
<em> </em><em> </em><em>=</em><em>1</em><em>/</em><em>2</em>
