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damaskus [11]
3 years ago
14

Jackson is designing a new heater, and he wants to experiment with different thermally conductive materials. Which of these mate

rials would be useful in conducting heat?
A.
cork
B.
wood
C.
soil
D.
aluminum
Mathematics
2 answers:
zubka84 [21]3 years ago
7 0
The answer is D: aluminum.
Leokris [45]3 years ago
4 0

Answer:

<h2>D. aluminum.</h2>

Step-by-step explanation:

Conductive materials refer to those materials which have lower resistance to the movement of electric charges, the higher this resistance, higher the conductivity, because electrons would move faster.

Think about friction, conductive materials have low friction for electrons to move, that's why the can easily conduct electricity, like metals.

Now, among the options, aluminum is a metal, which means it can easily conduct electric currents, thanks to its internal structure, electrons can travel faster than inside wood, cork or soil.

Therefore, the right answer is D. aluminum.

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Shen picks a rational number.What is true about the opposite of his number?
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A lot depends upon your interpretation of "opposite."  Do you mean "reciprocal?"

If you give the number a, the reciprocal would be 1/a.  Is that what you mean?

Or do you mean "the number with opposite sign?"  If you give the number b, "the number with opposite sign" would be -b.

Consider both cases.  Choose a rational number (such as 7/8).  Find the reciprocal of this number.  Find the number with opposite sign of this number.
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Step-by-step explanation:

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Hello!
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4/10

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4 0
4 years ago
Rewrite the statement in mathematical notation. (Let y be the distance from the top of the ladder to the floor, x be the distanc
In-s [12.5K]

Answer:

\frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}

Step-by-step explanation:

Let L be the length of the ladder,

Given,

x = the distance from the base of the ladder to the wall, and t be time.

y = distance from the base of the ladder to the wall,

So, by the Pythagoras theorem,

L^2 = y^2 + x^2

\implies L = \sqrt{y^2 + x^2},

Differentiating with respect to time (t),

\frac{dL}{dt}=\frac{d}{dt}(\sqrt{x^2 + y^2})

=\frac{1}{2\sqrt{x^2 + y^2}}\frac{d}{dt}(x^2 + y^2)

=\frac{1}{2\sqrt{x^2 + y^2}}(2x\frac{dx}{dt}+2y\frac{dy}{dt})

=\frac{1}{\sqrt{x^2 +y^2}}(x\frac{dx}{dt}+y\frac{dy}{dt})

Here,

\frac{dy}{dt}=-6\text{ ft per sec}

Also, \frac{dL}{dt} = 0           ( Ladder length = constant ),

\implies \frac{1}{\sqrt{x^2 +y^2}}(x(-6)+y\frac{dy}{dt})=0

-6x + y\frac{dy}{dt}=0

y\frac{dy}{dt}=6x

\implies \frac{dy}{dt}=\frac{6y}{x}\text{ ft per sec}

Which is the required notation.

8 0
3 years ago
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