Answer:
The probability that a call last between 4.2 and 4.9 minutes is 0.4599
Step-by-step explanation:
Let X be the length in minutes of a random phone call. X is a normal distribution with mean λ=4.2 and standard deviation σ=0.4. We want to know P(4.2 < X < 4.9). In order to make computations, we will use W, the standarization of X, given by the following formula

We will use
, the cummulative distribution function of W. The values of
are well known and the can be found in the attached file

We conclude that the probability that a call last between 4.2 and 4.9 minutes is 0.4599
Answer:
B) because 18 times 100 is equal to 5 times x, which means that x is equal to
Step-by-step explanation:
B is the only statement that is true
<em>If you use cross product property to solve these proportions B is the only one that is correct</em>
<em>A) 18/x and 5/100 </em><em>x= 360 not 36</em>
<em>B) 18/x and 5/100 </em><em>x=360</em>
<em>C) 18/100 and 5/x </em><em>x = 27.7 not 36</em>
<em>D) 18/100 and 5/x </em><em>x= 27.7 not 360</em>
To find this, you'll want to divide the amount of music by the total amount of time. 29/(9+12+29) = 29/50 = 58/100 = 58%
Given:

To find:
The exact value of cos 15°.
Solution:

Using half-angle identity:


Using the trigonometric identity: 

Let us first solve the fraction in the numerator.

Using fraction rule: 

Apply radical rule: ![\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7B%5Cfrac%7Ba%7D%7Bb%7D%7D%3D%5Cfrac%7B%5Csqrt%5Bn%5D%7Ba%7D%7D%7B%5Csqrt%5Bn%5D%7Bb%7D%7D)

Using
:


20% de 75 es 50...<span>Es el iniciador</span>