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Kitty [74]
3 years ago
14

WILL MARK BRAINLEST!!Use the remainder theorem to find T(2) for T(x)= 3x3 - 2x2 - 6x -5.

Mathematics
1 answer:
ddd [48]3 years ago
4 0

Answer:

B

Step-by-step explanation:

T(x)=3x³-2x²-6x-5

T(2)=3(2)³-2(2)²-6(2)-5

=24-8-12-5∵

=-1

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If you know the answer to this, please say it! Equation and all too! Thank you :DD
vlabodo [156]

Answer

x=33

Step-by-step explanation:

since they're both on the same line we must equal them to 180.

18 + x + 4x -3 = 180 (Now you simplify terms)

5x + 15 = 180 (Subtract the 15 from both sides)

5x = 165 (divide by 5 to isolate the variable)

x = 33 (Hope I was able to help :) )

6 0
3 years ago
Here are two points (-3,4),(1,7) What is the slope of the line between them?
valentina_108 [34]

Answer:

3/4

Step-by-step explanation:

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Ne4ueva [31]

Answer:

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Read 2 more answers
Consider the equation 5x^2-10x+c=0. What values of c result in the equation having a complex solutions? Represent your answer on
stiv31 [10]

Answer:

When we have a quadratic equation:

a*x^2 + b*x + c = 0

There is something called the determinant, and this is:

D = b^2 - 4*a*c

If D < 0, then the we will have complex solutions.

In our case, we have

5*x^2 - 10*x + c = 0

Then the determinant is:

D = (-10)^2 - 4*5*c = 100 - 4*5*c

And we want this to be smaller than zero, then let's find the value of c such that the determinant is exactly zero:

D = 0 = 100 - 4*5*c

    4*5*c = 100  

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            c = 100/20 = 5

As c is multiplicating the negative term in the equation, if c increases, then we will have that D < 0.

This means that c must be larger than 5 if we want to have complex solutions,

c > 5.

I can not represent this in your number line, but this would be represented with a white dot in the five, that extends infinitely to the right, something like the image below:

8 0
3 years ago
Which are are the roots of the quadratic function F(q)=q^2-125?
nadezda [96]
Q^2 - 125 = 0
q^2 = 125

q = +/- sqrt 125  =    11.18, -11.18
5 0
4 years ago
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