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3 years ago

WILL MARK BRAINLEST!!Use the remainder theorem to find T(2) for T(x)= 3x3 - 2x2 - 6x -5.

Mathematics

1 answer:

ddd [48]3 years ago

4 0

Answer:

Step-by-step explanation:

T(x)=3x³-2x²-6x-5

T(2)=3(2)³-2(2)²-6(2)-5

=24-8-12-5∵

=-1

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-5v+6=-12+62 What is v?

sattari [20]

Answer:

-8.8

Step-by-step explanation:

combine terms on right side of equal sign(50)

know your equation is -5v+6=50

subtract 6 from both sides so you know have -5v=44

then divide both sides by negative five so know you have v=-8.8

(plug in -8.8 to check)

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3 years ago

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“An architect is planning to incorporate several stone spheres of different sizes into the landscaping of a public park, and wor

Artist 52 [7]

Answer:

Part 1) The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Part 2) The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

Step-by-step explanation:

Step 1

Find the radius of each sphere

we know that

The circumference of a circle is equal to

$C=2\pi r$

Find the radius of the sphere with a 5.50-meter circumference

For $C=5.50\ m$

assume

$\pi =3.14$

substitute and solve for r

$5.50=2(3.14)r$

$r=5.50/[2(3.14)]=0.88\ m$

Find the radius of the sphere with a 7.85-meter circumference

For $C=7.85\ m$

assume

$\pi =3.14$

substitute and solve for r

$7.85=2(3.14)r$

$r=7.85/[2(3.14)]=1.25\ m$

step 2

Find the surface area of each sphere

The surface area of sphere is equal to

$SA=4\pi r^{2}$

Find the surface area of sphere with a 5.50-meter circumference

For $r=0.88\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(0.88)^{2}$

$SA=9.73\ m^{2}$

Find the surface area of sphere with a 7.85-meter circumference

For $r=1.25\ m$

assume

$\pi =3.14$

substitute

$SA=4(3.14)(1.25)^{2}$

$SA=19.63\ m^{2}$

step 3

Find the cost of finishing each sphere

we know that

To find out the cost , multiply the surface area by $92 per square meter

Find the cost of sphere with a 5.50-meter circumference

$9.73*(92)=\$895.16$

therefore

The value that is closest to the cost of finishing a sphere with a 5.50-meter circumference is $900

Find the cost of sphere with a 7.85-meter circumference

$19.63*(92)=\$1,805.96$

therefore

The value that is closest to the cost of finishing a sphere with a 7.85-meter circumference is $1,800

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3 years ago

The figure shown in the right is made up of a square and a circle. Find the perimeter of the shaded region.

Tasya [4]

Answer:

B. 12 + 2pi cm

Step-by-step explanation:

The shaded region is made up of 3 square sides and one half circle. The three square sides are each 4, which means that those altogether equal 12.

The circle's circumference can be found by using the equation c = (d)pi

The diameter is 4, so the whole circumference is 4pi. However, you only need half of a circle, which is represented by 2pi.

Add them all together, and you get 12 + 2pi cm.

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musickatia [10]

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3 years ago

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How would 9/25 as a percent

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36% is the answer to the question

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