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3 years ago

Why might lower atmospheric pressure related to faster wind speed??

Physics

1 answer:

Travka [436]3 years ago

8 0

The only DIRECT relationship between the two is when you are dealing with upper level winds.

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In rules for naming a compound you change the negative name to end in" ide" *

Strike441 [17]

Answer:

Single-atom negative ions end in “-ide”, so binary compounds always have this ending. Polyatomic compounds usually end in “-ate” or “-ite”. FORMULAS: Write the positive ion, with its charge, then the negative ion, with its charge.

Explanation:

hope it helps, please mark as brainliest

8 0

3 years ago

Which group has the Same electron shells? A Titanium and Gold B Selenium and Tin C Calcium and Magnesium D Lithium and Boron

Anna11 [10]

im not 100 percent sure but i think its b

6 0

3 years ago

A 100-g toy car is propelled by a compressed spring that starts it moving. the car follows a curved track. what is the final spe

wel

Answer:

0.687 m/s

Explanation:

Initial energy = final energy

1/2 mu² = mgh + 1/2 mv²

1/2 u² = gh + 1/2 v²

Given u = 2.00 m/s, g = 9.8 m/s², and h = 0.180 m:

1/2 (2.00 m/s)² = (9.8 m/s²) (0.180 m) + 1/2 v²

v = 0.687 m/s

5 0

3 years ago

Read 2 more answers

An explorer is caught in a whiteout (in which the snowfall is so thick that the ground cannot be distinguished from the sky) whi

Veronika [31]

Answer:

$s=5.79\ km$

$\theta=47^{\circ}$ east of south

Explanation:

Given:

distance of the person form the initial position, $d'=8.4\ km$

direction of the person from the initial position, $47^{\circ}$ north of east

distance supposed to travel form the initial position, $d=5.3\ km$

direction supposed to travel from the initial position, due North

Now refer the schematic for visualization of situation:

$y=d'.\sin47^{\circ}-d$

$y=8.4\times \sin47-5.3$ ...............(1)

$x=d'.\cos47^{\circ}$

$x=8.4\times \cos47^{\circ}$ .................(2)

Now the direction of the desired position with respect to south:

$\tan\theta=\frac{y}{x}$

$\tan\theta=\frac{8.4\times \sin47}{8.4\times \cos47}$

$\theta=47^{\circ}$ east of south

Now the distance from the current position to the desired position:

$s=\sqrt{x^2+y^2}$

$s=\sqrt{(8.4\times \cos47)^2+(8.4\times \sin47-5.3)^2}$

$s=5.79\ km$

4 0

3 years ago

PLS ANSWER FAST WILL GIVE BRAINLEST!!!

Kipish [7]

Answer:

2 Newtons

Explanation:

$F = ma$

Therefore, your mass would be 1kg and your acceleration would be 2m/s/s

Plug the numbers into the equation:

$(1kg)(2m/s/s)$

which will equal

$2 Newtons$

8 0

3 years ago