If F1 = 104 and F2 = 104, what will be the net force?
1 answer:
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You traveled a distance of 620.075 meters if it takes you 8.5 seconds to stop.
<u>Given the following data:</u>
- Initial velocity, U = 31.3 m/s
- Time, t = 8.5 seconds.
We know that acceleration due to gravity (a) for an object is equal to 9.8 meter per seconds square.
To find the distance traveled, we would use the second equation of motion:
Mathematically, the second equation of motion is given by the formula;
Where:
- S is the distance travelled.
- u is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
Substituting the parameters into the formula, we have;
<em>Distance, S</em><em> = </em><em>620.075 meters.</em>
Therefore, you traveled a distance of 620.075 meters if it takes you 8.5 seconds to stop.
Read more: brainly.com/question/8898885
The initial velocity of the cat is 56.6 m/s
Explanation:
The motion of the cat is a projectile motion, consisting of:
- a uniform horizontal motion with constant velocity
- a vertical accelerated motion with constant acceleration (free fall)
We start by analyzing the vertical motion, to find the time it takes for the cat to reach the ground. We use the following suvat equation:
where we have (choosing downard as positive direction)
s = 125 m is the vertical displacement of the cat
u = 0 is the initial vertical velocity
t is the time taken to reach the ground
is the acceleration of gravity
Solving for t, we find
Now we can analzye the horizontal motion. Since the motion is uniform and the horizontal velocity is constant, it is given by
where
d = 286 m is the horizontal distance travelled
t = 5.05 s is the time taken
Solving the equation,
Learn more about projectile motion:
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