The compressional forces stemming from a convergent plate boundary.
There will also be earthquakes along the plate margin. This is also referred to as a collision boundary.
Hope this helps
Sound waves actually travel much faster in water than air, but words and the direction of the noise are distorted.
To solve this problem we will apply the concepts related to the Doppler Effect, defined as the change in apparent frequency of a wave produced by the relative movement of the source with respect to its observer. Mathematically it can be written as

Here,
= Frequency of the source
= Speed of the sound
= Speed of source
Now the velocity we have that


Then replacing our values,


Therefore the frequency of the observer is 1047.86Hz