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3 years ago

25x^2+1=5 quadratic

1 answer:

3 0

25x² + 1 = 5

25x² + 1 - 5 = 0

25x² - 4 = 0 By difference of two squares

(5x)² - (2)² = 0

(5x - 2)(5x + 2) = 0

5x - 2 = 0 or 5x + 2 = 0

5x = 0 + 2 5x = 0 - 2

5x = 2 5x = -2

x = 2/5 x = -2/5

x = 0.4 x = -0.4

x = + 0.4 or -0.4

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The number is 17

Step-by-step explanation:

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2 years ago

PLSSS HELP!! For the given ordered pairs, write a function rule relating x and y. (1,4), (2,9), (3,16), (4,25)

LenKa [72]

Answer:

y=(x+1)^2

Step-by-step explanation:

we have the following

$x=1;y=4\\\\x=2;y=9\\\\x=3;y=16\\\\x=4;y=25$

the values of y are squares so we can write

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$y=(x+1)^2$

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3 years ago

Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean

Leno4ka [110]

Answer:

a = $\sqrt{7}$

Step-by-step explanation:

I think your question is missed of key information, allow me to add in and hope it will fit the original one.:

Suppose ABC is a right triangle with sides a, b, and c and right angle at C. Find the unknown side length using the Pythagorean theorem and then find the values of the six trigonometric functions for angle B. when b=3 and c=4.

My answer:

We will Pythagoras theorem, which states that the sum of squares of two legs of a right triangle is equal to the square of the hypotenuse of right triangle. Because the question says that ABC is a right triangle.

$a^2+b^2=c^2$

Given that: b=3 and c=4

$a^2+3^2=4^2a^2+9=16a^2+9-9=16-9a^2=7$

so a = $\sqrt{7}$

We know that tangent relates opposite side of a right triangle with adjacent side.

$\text{tan}(B)=\frac{a}{b}\\\text{tan}(B)=\frac{\sqrt{7}}{3}$

Please have a look at the attached photos.

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3 years ago

Graph the line with slope −3/4 passing through the point , (3,3)

Nookie1986 [14]

Y = mx + b
slope(m) = -3/4
(3,3)....x = 3 and y = 3
now we sub and find b, the y int
3 = -3/4(3) + b
3 = -9/4 + b
3 + 9/4 = b
12/4 + 9/4 = b
21/4 = b.....or 5.25 for graphing purposes

so ur equation is : y = -3/4x + 21/4

ur y int = (0,21/4) or (0,5.25)

ur x int can be found by subbing in 0 for y and solving for x
y = -3/4x + 21/4
0 = -3/4x + 21/4
3/4x = 21/4
x = 21/4 * 4/3
x = 84/12 = 7.....so ur x int is (7,0)

so plot ur points (7,0) and (0,5.25)....now start at (0,5.25) and since the slope is -3/4, come down 3 spaces and go to the right 4 spaces, then down 3, and to the right 4 and u will eventually cross the x axis at (7,0)

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3 years ago