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3 years ago

1-Andrea tenía una deuda de $25 850 en el banco y abonó $18700. ¿Cuál es su deuda actualmente?

Mathematics

1 answer:

lora16 [44]3 years ago

6 0

Answer:

Current debt of Andrea = $7,150

Step-by-step explanation:

Given:

Loan taken by Andrea from bank = $25,850

Amount paid by Andrea to bank = $18,700

Find:

Current debt of Andrea

Computation:

⇒ Current debt of Andrea = Loan taken by Andrea from bank - Amount paid by Andrea to bank

⇒ Current debt of Andrea = 25,850 - 18,700

Current debt of Andrea = $7,150

Note: O information provide about interest.

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Suppose that an airline quotes a flight time of 128 minutes between two cities. Furthermore, suppose that historical flight reco

ANTONII [103]

Answer:

(a) The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

(b) The value of P (129 ≤ X ≤ 146) is 0.3462.

(c) The probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

Step-by-step explanation:

The random variable X is defined as the flight time between the two cities.

Since the random variable X denotes time interval, the random variable X is continuous.

(a)

The random variable X is Uniformly distributed with parameters a = 10 minutes and b = 154 minutes.

The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

(b)

Compute the value of P (129 ≤ X ≤ 146) as follows:

Apply continuity correction:

P (129 ≤ X ≤ 146) = P (129 - 0.50 < X < 146 + 0.50)

= P (128.50 < X < 146.50)

$=\int\limits^{146.50}_{128.50} {\frac{1}{154-102}} \, dx$

$=\frac{1}{52}\times \int\limits^{146.50}_{128.50} {1} \, dx$

$=\frac{1}{52}\times (146.50-128.50)$

$=0.3462$

Thus, the value of P (129 ≤ X ≤ 146) is 0.3462.

(c)

It is provided that a randomly selected flight between the two cities will be at least 3 minutes late, i.e. X ≥ 128 + 3 = 131.

Compute the value of P (X ≥ 131) as follows:

Apply continuity correction:

P (X ≥ 131) = P (X > 131 + 0.50)

= P (X > 131.50)

$=\int\limits^{154}_{131.50} {\frac{1}{154-102}} \, dx$

$=\frac{1}{52}\times \int\limits^{154}_{131.50} {1} \, dx$

$=\frac{1}{52}\times (154-131.50)$

$=0.4327$

Thus, the probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

6 0

3 years ago

Use properties of shapes and angles to find the missing measures.

guapka [62]

Answer:

< 1 = 130°, < 2 =50°, < 3 = 50°, < 4= 30°, < 5 = 70°, < 6 = 50°, < 7= 60°, < 8 = 40°, < 9 = 40°, < 10 = 50°, < 11 = 50°, < 12 = 130°, < 13 = 140°, < 14 =40° , < 15 = 140°

Step-by-step explanation:

< 4 = 90- 60 = 30° because angle 4 and angle 60° are complementary

< 5 = 70°, because vertical angles are congruent

< 2 = 180-130 = 50 °, because 130 ° and 2 are a linear pair

< 6 = 180-130 = 50 °, because 130 ° and 2 are a linear pair

because < 2 = < 6 and are alternate exterior angles then two lines are parallel

<13 = 140°, corresponding angles

< 13 = < 15 = 140°, vertical angles

< 8 = < 9 = < 14 = 180-140 = 40°, linear pair and vertical angles

< 3 = 180-90-40= 50 °, because the sum off all angles in a Δ is 180°

< 3= < 10 = < 11 =50° vertical angles , and corresponding angles

< 7= 180 -70 -50 = 60°, because the sum off all angles in a Δ is 180°

<1 = <12 = 180 -50 = 130°, linear pair and vertical angles

4 0

3 years ago

At 7:00 p.m., there are 1,000 home-team fans and 700 away-team fans at a football game. After 7:00 p.m, 15 home team fans arrive

OleMash [197]

Answer:

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=109:67

Step-by-step explanation:

Initially , total home team fans =1000

and away team fans = 700.

7:00 pm to 8:00 pm = 1 hour = 60 minutes

Given that

Every 10 minutes the number of arrival home team fans is 15.

Then in 1 minutes the number of arrival home team fans is $\frac{15}{10}$

and in 60 minutes the number of arrival home team fans is $\frac{15 \times 60}{10}$

=90

Therefore total home team fans = (90+1000)=1090

Given that

Every 10 minutes 5 fans leave of away team leave.

then in 1 minutes $\frac{5}{10}$ fans leave of away team leave.

and In 60 minutes $\frac{5\times 60}{10}$ =30 fans leave of away team leave.

Since 30 away team fans leave.

Total away team fans = (700-30)=670

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=1090:670

=109:67

4 0

3 years ago

Heyy can you please help me posted picture of question

vichka [17]

We can use quadratic formula to determine the roots of the given quadratic equation.

The quadratic formula is:

$x= \frac{-b+- \sqrt{ b^{2} -4ac} }{2a}$

b = coefficient of x term = 4
a = coefficient of squared term = 1
c = constant term = 7

Using the values, we get:

$x= \frac{-4+- \sqrt{16-4(1)(7)} }{2(1)} \\ \\ 
x= \frac{-4+- \sqrt{-12} }{2} \\ \\ 
x= \frac{-4+-2 \sqrt{-3} }{2} \\ \\ 
x= -2+- \sqrt{-3}$

So, the correct answer to this question is option A

7 0

3 years ago

What is the probability that 6 rolls of a fair die will show four exactly 5 times?

storchak [24]

Answer:

very less

Step-by-step explanation:

When rolling a fair 6 sided die 5 times there are 6^5 possible combinations.

Of those, there are 5 ways to roll exactly four sixes, and each of those ways have 5 possible results on the die which has not rolled a six, plus there is 1 way to roll five sixes. 5*5+1=26 combinations with at least four sixes.

Now, take the number of results which fit your conditions, divide by the number of possible results and you get your answer: 26/7776 which can be reduced to 13/3338, a bit less than 0.4%

6 0

3 years ago