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omeli [17]
3 years ago
9

The thirrdgrade Class Is GOING ON A FIELD TRIP BY BUS TO THE MUESUEM THE BUS LEAVES THE SCHOOL AT 9;45 A.M. THE BUS RIDE TAKES 4

7 MINUTES AT WHAT TIME DOES THE BUS ARRIVE AT THE MUSEEUM///////////////////
Mathematics
1 answer:
torisob [31]3 years ago
7 0
9:60 is one hours
it takes 15 mins to get to 60
47-15=32

9:45+47=9:45+15:32=10:00+32=10:32 AM
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Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

Step-by-step explanation:

We have the following info given:

Confidence= 0.95 the confidence level desired

ME =0.03 represent the margin of error desired

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

The confidence level is 95% or 0.95, the significance is \alpha=0.05 and the critical value for this case using the normal standard distribution would be z_{\alpha/2}=1.96

Since we don't have prior information we can use \hat p= 0.5 as an unbiased estimator

Also we know that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11  

And rounded up we have that n=1068

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