A screen door spring has a spring constant of 188 N/m, and stretches 0.292 m when the door is opened. What force does it exert?
2 answers:
Answer:
54.846N
Step-by-step explanation:
Force = ?
Spring constant (K) = 188N/m
Spring stretch (x) = 0.292m
Force acting on a spring = spring constant * spring stretch
Force = 188 * 0.292
Force = 54.896N
The force acting on the spring is 54.896N
Answer:
The answer is 54.896N
Step-by-step explanation:
From Hooke's law,
Force = spring constant x extension
i.e
F = k x e
F = 188N/m x 0.292m
F = 54.896N
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