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Tema [17]
3 years ago
14

A screen door spring has a spring constant of 188 N/m, and stretches 0.292 m when the door is opened. What force does it exert?

Mathematics
2 answers:
guajiro [1.7K]3 years ago
6 0

Answer:

54.846N

Step-by-step explanation:

Force = ?

Spring constant (K) = 188N/m

Spring stretch (x) = 0.292m

Force acting on a spring = spring constant * spring stretch

Force = 188 * 0.292

Force = 54.896N

The force acting on the spring is 54.896N

Rudik [331]3 years ago
5 0

Answer:

The answer is 54.896N

Step-by-step explanation:

From Hooke's law,

Force = spring constant x extension

i.e

F = k x e

F = 188N/m x 0.292m

F = 54.896N

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An hour before show​ time, only 266 people are seated for a movie. . According to ticket​ sales, 93​% of the people have yet to
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3800 tickets

Step-by-step explanation:

we are given that,

total people seated:266

yet to come:93%

so the percentage of people who have arrived is 100%-93%=7%

and one ticket for each people

therefore,

\displaystyle \begin{array}{ccc} \displaystyle \rm7\%   \quad \text{People} \implies266 \:  \text{tickets} \\  \displaystyle100 \%\:   \quad \imath \imath \implies   \frac{266}{7\%}   \:  \:  \:  \: \imath  \imath \\ \\   \qquad  \displaystyle    \qquad\rm as  \: \% =    \frac{1}{100} \longleftarrow \frac{266}{ \dfrac{7}{100} }     \\   \\  \displaystyle   \rm  \: by \: simplifying \: complex \: fraction\longleftarrow 266  \times  \frac{100}{7}   \\  \rm reduce \: fraction \longleftarrow 38 \times 100  \\  \rm simplify \:multiplication  \longleftarrow3800\end{array}

hence,

<u>3</u><u>8</u><u>0</u><u>0</u> tickets were sold for the movie

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2 years ago
Read 2 more answers
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