Answer: 0.02257
Step-by-step explanation:
Given : Total cards in a deck = 52
Number of ways to select any 5 cards : 
Since , there are total 13 kinds of card (includes Numbers from 2 to 9 and Ace , king, queen and jack).
Of each kind , there are 4 cards.
Number of ways to select three cards in a five card hand of a single kind : 
Number of ways to select three cards in a five card hand of a exactly three of a kind : 
Now , the required probability = 
∴ The probability of being dealt exactly three of a kind (like three kings or three 7’s, etc.) in a five card hand from a deck of 52 cards= 0.02257
Answer: C. (2, -4)
Step-by-step explanation:
Take into consideration that y is less than or equal to -2. The only option in which the y value is less than or equal to -2 is option C., thus C would correctly solve the system of inequalities.
Answer:
2)8%
3)=
$
26.46
4)multiply $1.50 and 60%, which will give you 0.9. now multiply $1.50 and 0.9 and that'll give you$1.35. lastly, add $1.50 and $1.35 and that'll give you the answer which is $2.85.
5)15 % of $1580 is $237
6)25%
Step-by-step explanation:
Please mark brainliest
bc i answered all of them
-yasmine
Step-by-step explanation:
Domain of a rational function is everywhere except where we set vertical asymptotes. or removable discontinues
Here, we have
First, notice we have x in both the numerator and denomiator so we have a removable discounties at x.
Since, we don't want x to be 0,
We have a removable discontinuity at x=0
Now, we have
We don't want the denomiator be zero because we can't divide by zero.
so
So our domain is
All Real Numbers except-2 and 0.
The vertical asymptors is x=-2.
To find the horinzontal asymptote, notice how the numerator and denomator have the same degree. So this mean we will have a horinzontal asymptoe of
The leading coeffixent of the numerator/ the leading coefficent of the denomiator.
So that becomes
So we have a horinzontal asymptofe of 2
