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3 years ago

Unit rates! PLZ HELP WILL GIVE BRAINIEST!!

Mathematics

1 answer:

Alchen [17]3 years ago

3 0

Answer:

The answer is $10.32aprox

Step-by-step explanation:

I hope it will help u

Please mark me as brainlist

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F(x)=-5x. g(x)=8x^2-5x-9. Find: (f*g) (x)

Troyanec [42]

F(x) = -5x
g(x) = 8x² - 5x - 9

(f×g)(x) = ?
= ((-5x)(8x²-5x-9))
= -40x³ + 25x² + 45x → The answer Opsi D

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4 years ago

Can someone help me please?

IgorLugansk [536]

Answer:

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Step-by-step explanation:

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3 years ago

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I think that is correct answer but can you please help me

pochemuha

Yes you are right. it's 132

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3 years ago

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Write a multiplication equation using one whole number and one fraction that have a product of 18/8

Digiron [165]

Answer:

whole number = 8

fraction = 1/8

1/8 * 18 = 18/8

Step-by-step explanation:

fraction times a whole number = 18/8

1/8 * 18 = 18/8

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3 years ago

Help me please ;-;!!!!! Use a coordinate grid to create a map of a town with at least five different locations, such as a house,

Sholpan [36]

A. Our diagram have six location: my house (2,1), a movie theater (5,3), the school (6,6), the police station (3,-2), the airport (-3,3), and the mall (-2,-3)

B. Distance between my house and the movie theater:
To calculate the distance we are going to use the points (2,1) and (5,3) to create a right triangle with tow legs of measures 3 and 2; the hypotenuse of the right triangle will be the distance between my house and the movie theater.
Using the Pythagorean theorem:
$d^2=3^2+2^2$
$d^2=9+4$
$d^2=13$
$d= \sqrt{13}$
We can conclude that the distance between my house and the movie theater is $\sqrt{13}$

Our second distance is the distance between the police station and the airport:
This time we are using the points (3,-2) and (-3,3) to create a right triangle with legs of measures 6 and 5; the hypotenuse of our triangle will be the the distance between our points:
$d^2=6^2+5^2$
$d^2=36+25$
$d^2=61$
$d= \sqrt{61}$
We can conclude that the distance between the police station and the airport is $\sqrt{61}$

C. Distance form the park to the Fire Station:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance from the park to the Fire Station is $\sqrt{10}$

Distance from the stadium to the mall:
$d^2=2^2+1^2$
$d^2=4+1$
$d^2=5$
$d= \sqrt{5}$
We can conclude that the distance from the stadium to the mall is $\sqrt{5}$

D. What is the distance between your house and the mall?
Answer:
$d^2=4^2+4^2$
$d^2=16+16$
$d^2=32$
$d= \sqrt{32}$
$d=4 \sqrt{2}$
We can conclude that the distance between my house and the mall is $4 \sqrt{2}$

What is the distance between the movie theater and the school?
answer:
$d^2=3^2+1^2$
$d^2=9+1$
$d^2=10$
$d= \sqrt{10}$
We can conclude that the distance between the movie theater and the school is $\sqrt{10}$

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3 years ago