Answer:
NO amount of hour passed between two consecutive times when the water in the tank is at its maximum height
Step-by-step explanation:
Given the water tank level modelled by the function h(t)=8cos(pi t /7)+11.5. At maximum height, the velocity of the water tank is zero
Velocity is the change in distance with respect to time.
V = {d(h(t)}/dt = -8π/7sin(πt/7)
At maximum height, -8π/7sin(πt/7) = 0
-Sin(πt/7) = 0
sin(πt/7) = 0
Taking the arcsin of both sides
arcsin(sin(πt/7)) = arcsin0
πt/7 = 0
t = 0
This shows that NO hour passed between two consecutive times when the water in the tank is at its maximum height
Answer:
1/4
Step-by-step explanation:
2/3 multiply top and bottom of fraction by 2
4/6 is the capacity of the container
1/6 is filled
so 1/4 of the container is filled
The first one because it has a negative slope (which is -4) and h is always the opposite while k stays the same. By the way h is the 2 and k is the 3
Eh I would personally say that your getting more if you do 96 it is more expensive but don’t get 64
The restrictions are:
1) x ≥ 0
2) number of lower bowl seats = 65% * 18500 = 12,025
=> x ≤ 12,025
3) y ≥ 0
4) number of upper bowl seats = 35% * 18500 = 6,475
=> y ≤ 6,475
It is not necessary to state that x + y ≤ 18,500 because it is included in the other restrictions.
