Direct variation is y=kx where k is a constant
the fiest way to see if it is direct or not, is if x increases, then y increases as well,
then we see if y=kx is valid, basically if we have a constant of variation
the first one x increase and y increase
see if same constant
y=kx
-4.5=-3k
1.5=k
so
see next one
-1 and 3
-3=-1(k)
-3=-1(1.5)
-3=-1.5
false
not it
2nd is increase and y decrease, so not direct variation
3rd is x is same but y increase so nope
4th is x increase and y increase, now test the constant
-7.5=-3k
2.5=k
-1 and -2.5
-2.5=-1k
-2.5=-1(2.5)
-2.5=-2.5
true
answer is last option
Answer:
∠B = 62°
Step-by-step explanation:
Because ∠A and ∠B are vertical angles they are equal hence we can write
∠A = ∠B
8x + 14 = 2x + 50
Now we have to solve for x
To do so, subtract 2x on both sides of the equation:
6x + 14 = 50
Now, subtract 14 on both sides of the equation
6x = 36
Now, divide 6 on both sides of the equation
x = 6
To find m∠B you have to you have to plug in x = 6 back into the ∠B equation
∠B = 2(6) + 50
∠B = 62°
Answer:
x=−2
Step-by-step explanation:
1 Expand.
6-2x-12=3x+4
6−2x−12=3x+4
2 Simplify 6-2x-126−2x−12 to -2x-6−2x−6.
-2x-6=3x+4
−2x−6=3x+4
3 Add 2x2x to both sides.
-6=3x+4+2x
−6=3x+4+2x
4 Simplify 3x+4+2x3x+4+2x to 5x+45x+4.
-6=5x+4
−6=5x+4
5 Subtract 44 from both sides.
-6-4=5x
−6−4=5x
6 Simplify -6-4−6−4 to -10−10.
-10=5x
−10=5x
7 Divide both sides by 55.
-\frac{10}{5}=x
−
5
10
=x
8 Simplify \frac{10}{5}
5
10
to 22.
-2=x
−2=x
9 Switch sides.
x=-2
x=−2
The seventh term of the sequence is
-1
—
25
Answer:
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
Step-by-step explanation:
Consider the provided information,
Let X is the number of defective bulbs.
Ten light bulbs are randomly selected.
The likelihood that a light bulb is defective is 5%.
Therefore sample size is = n = 10
Probability of a defective bulb = p = 0.05.
Therefore, q = 1 - p = 1 - 0.05 = 0.95
Mean of binomial random variable: 
Therefore, 
Variance of binomial random variable: 
Therefore, 
Mean and Variance of the number of defective bulbs are 0.5 and 0.475 respectively.
