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NARA [144]
3 years ago
7

I need help answering these questions, methods appreciated on how to do each one.

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

get rickrolled

Step-by-step explanation:

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Find the volume of the given solid: Bounded by the cylinder y^2+z^2=4 and the planes x = 2y, x = 0, z = 0 in the first octant.
rodikova [14]

The solution would be like this for this specific problem:

<span>V = ∫ dV </span><span>
<span>= ∫0→2 ∫ 0→π/2 ∫ 0→ 2·r·sin(φ) [ r ] dzdφdr </span>
<span>= ∫0→2 ∫ 0→π/2 [ r·2·r·sin(φ) - r·0 ] dφdr </span>
<span>= ∫0→2 ∫ 0→π/2 [ 2·r²·sin(φ) ] dφdr </span>
<span>= ∫0→2 [ -2·r²·cos(π/2) + 2·r²·cos(0) ] dr </span>
<span>= ∫0→2 [ 2·r² ] dr </span>
<span>= (2/3)·2³ - (2/3)·0³ </span>
<span>= 16/3 </span></span>

So the volume of the given solid is 16/3. I am hoping that these answers have satisfied your query and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.

3 0
3 years ago
Jadyn prepares a bag of candy before a road trip. The bag contains individual pieces of Skittles, M&amp;Ms, Life Savers and Sour
kipiarov [429]

Given condition is- The bag contains individual pieces of Skittles, M&Ms, Life Savers and Sour Patch Kids.

Let the total number of candies in the bag be = x

Then, Skittles are \frac{1x}{2}

Candies left = x-\frac{x}{2} = \frac{x}{2}

M&Ms are = \frac{1x}{8}

Now remaining candies are= \frac{3x}{8}

Now Life savers are = \frac{9x}{32}

Now adding all these 3 candies

\frac{x}{2}+ \frac{x}{8}+\frac{9x}{32}

=\frac{29x}{32}

Now the remaining candies sour patch will be =

x-\frac{29x}{32} =\frac{3x}{32}

Hence, sour patch kids are \frac{3}{32}

3 0
3 years ago
Find the difference. express your answer in simplest form. (2s/s^2-4s+4) - (4/s^2-4s+4)
LUCKY_DIMON [66]
To find the difference, we are going to destroy the parenthesis first, and then, we are going to perform the operations. Remember that to destroy a parenthesis preceded by a negative sign (-), you should change the signs of the factors inside the parenthesis:
\frac{2s}{s^2-4s+4} -( \frac{4}{s^2-4s+4} )
\frac{2s}{s^2-4s+4} -\frac{4}{s^2-4s+4}= \frac{2s-4}{s^2-4s+4}

Now we can factor both numerator and denominator and simplify:
\frac{2s-4}{s^2-4s+4} = \frac{2(s-2)}{(s-2)^2} = \frac{2}{s-2}

We can conclude that the difference in simplest form is: \frac{2}{s-2}
5 0
3 years ago
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I need help finding the circumference of this circle ​
Alla [95]
Radius times 2 = diameter which would be 10 times 3.14 is 31.4 so it’s 31.4
6 0
3 years ago
You are given the following information about y and x. Y X Dependent Independent Variable Variable 5 15 7 12 9 10 11 7The least
nikitadnepr [17]
what in the- that’s so confusing wth
4 0
3 years ago
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