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Harlamova29_29 [7]
4 years ago
8

The length of a rectangle represented by 4a plus 3B and it's width is represented by 3a minus 2b. Write a polynomial for the per

imeter of the rectangle. What is the minimum perimeter of the rectangle if a equals 12 and b equals a non zero number?
Mathematics
1 answer:
Svetach [21]4 years ago
7 0
The polynomial for the perimeter starts from the formula for the perimeter of a rectangle as written below:

Perimeter = 2L + 2W = 2( L + W)
Perimeter = 2(4A + 3B + 3A - 2B)
Perimeter = 2(7A - B)
Let perimeter be P,
P = 14A - 2B  --> this would be the polynomial

Let's substitute A=12 to the polynomial:
P = 14(12) - 2B = 168 - 2B
To determine the minimum P, set it to 0.0001.
0.0001 = 168 - 2B
B = 83.999 or 84

Thus, the minimum perimeter is achieved if the value of B approached to 84.

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The following data represent the pH of rain for a random sample of 12 rain dates in Tucker County, West Virginia. A normal proba
Sphinxa [80]

Answer:

Step-by-step explanation:

n = 12

Mean = (4.58 + 5.72 + 4.77 + 4.76 + 5.19 + 5.05 + 4.80 + 4.77 + 4.75 + 5.02 + 4.74 + 4.56)/12 = 4.8925

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (4.58 - 4.8925)^2 + (5.72 - 4.8925)^2 + (4.77 - 4.8925)^2 + (4.76 - 4.8925)^2 + (5.19 - 4.8925)^2 + (5.05 - 4.8925)^2 + (4.80 - 4.8925)^2 + (4.77 - 4.8925)^2 + (4.75 - 4.8925)^2 + (5.02 - 4.8925)^2 + (4.74 - 4.8925)^2 + (4.56 - 4.8925)^2 = 1.122225

Standard deviation = √(1.122225/12

s = 0.31

a) Point estimate = sample mean = 4.8925

Confidence interval is written in the form,

(Sample mean - margin of error, sample mean + margin of error)

Margin of error = z × s/√n

Where

From the information given, the population standard deviation is unknown and the sample size is small, hence, we would use the t distribution to find the z score

In order to use the t distribution, we would determine the degree of freedom, df for the sample.

df = n - 1 = 12 - 1 = 11

b) Since confidence level = 95% = 0.95, α = 1 - CL = 1 – 0.95 = 0.05

α/2 = 0.05/2 = 0.025

the area to the right of z0.025 is 0.025 and the area to the left of z0.025 is 1 - 0.025 = 0.975

Looking at the t distribution table,

z = 2.201

Margin of error = 2.201 × 0.31/√12

= 0.197

95% confidence interval = 4.8925 ± 0.197

Upper limit = 4.8925 + 0.197 = 5.0895

Lower limit = 4.8925 - 0.197 = 4.6955

We are 95% confident that the population mean of the rain water ph lies between 4.6955 and 5.0895

c) For 99% confidence level, z = 3.106

Margin of error = 3.106 × 0.31/√12

= 0.278

99% confidence interval = 4.8925 ± 0.278

Upper limit = 4.8925 + 0.278 = 5.1705

Lower limit = 4.8925 - 0.278 = 4.6145

We are 99% confident that the population mean of the rain water ph lies between 4.6145 and 5.1705

d) The interval gets wider as the confidence level is increased. This is logical since the test score is higher for 99% and therefore, increases the range of values. Since we want to be more confident, the range of values must be extended.

3 0
4 years ago
This line has a slope<br> of -3 and passes<br> through the point<br> (4, -10)
ANEK [815]

Answer:

Step-by-step explanation:

y= mx+c

-10= -3 x 4 +c

-10= -12 +c

c= 2

then, y= -3x+2 would be the answer, if you were wanting the equation of the line.

8 0
3 years ago
Read 2 more answers
What is the measure of RPQ
patriot [66]

Answer:

239

Step-by-step explanation:

SP is the diameter so Arc RP is supplementary to Arc SR

31 + x = 180

x = 149

Arc PQ is supplementary to Arc SQ so

90 +  x = 180

x = 90

Arc Addition:

149 + 90 = 239

8 0
3 years ago
Write algebraic expression<br> 17 less than the product of 3 and m
motikmotik
"17 less than" implies subtraction of the product of 3 and m, so the equation would be, if solving for x:
x=3m-17
4 0
4 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7By%7D%20%3D%20a%28c%20%2B%20%20%5Cfrac%7B1%7D%7Bx%7D%29" id="TexFormula1" t
gulaghasi [49]

Greetings from Brasil...

Here we don't have much to go

∛Y = A.(C + 1/X)

∛Y = (AC + A/X)

raising both members to the cube.....

(∛Y)³ = (AC + A/X)³

from Notable Products: (a + b)³ = a³ + 3a²b + 3ab² + b³

Y = (AC)³ + 3(AC)².(A/X) + 3AC(A/X)² + (A/X)³

Y = A³[C³ + (3C²/X) + (3C/X²) + (1/X³)]

5 0
3 years ago
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