4 + 5x = 3 (-x + 3) -11

zaharov [31]

To do solve this you must isolate x. First subtract 16 to both sides (what you do on one side you must do to the other). Since 16 is being added to x, subtraction (the opposite of addition) will cancel it out (make it zero) from the left side and bring it over to the right side.

x + (16 - 16) = 24 - 16

x = 8

Check:

8 + 16 = 24

24 = 24

Hope this helped!

~Just a girl in love with Shawn Mendes

7 0

3 years ago

Read 2 more answers

2 bags of marshmallows are shared equally among 5 people.

exis [7]

Answer:

2/5 or 40% of a bag

Step-by-step explanation:

2 bags/5 people

goes to 2/5

which is equal to 4/10

also equal to 40/100

we can rewrite this as a percenatge 40%

Therefore each person gets 40% of a bag of marshmellows

7 0

3 years ago

Read 2 more answers

Consuela earns a salary of 40000$ per year plus commission of 1000$ for each car she sells. Write and solve an equation that sho

iVinArrow [24]

40000+1000x=60000
-40000. -40000

1000x=20000
x=20

6 0

3 years ago

If XY × 8 = YYY, where Xand Y are digits of the numbers, then what is the value of Y?

kakasveta [241]

Given that
XY*8 = YYY ⇒⇒⇒ Where X and Y are digits
So, X is equal to one of the digits from 1 to 9
and Y is one of the digits from 1 to 9
This can be solved as following
YYY = 100Y + 10Y + Y = Y(100+10+1) = 111Y
XY*8 = 8 (10X + Y) = 80X + 8Y
∴ 80X + 8Y = 111Y
∴ 80 X = 111Y - 8 Y
∴ 80 X = 103 Y

∴ Y = 80X/103
substitute with X = 1 to 9
X = 1 ⇒⇒⇒ Y = 0.77 ⇒⇒ unacceptable

X = 2 ⇒⇒⇒ Y = 1.55 ⇒⇒ unacceptable
X = 3 ⇒⇒⇒ Y = 2.33 ⇒⇒ unacceptable
X = 4 ⇒⇒⇒ Y = 3.11 ⇒⇒ unacceptable
X = 5 ⇒⇒⇒ Y = 3.88 ⇒⇒ unacceptable
X = 6 ⇒⇒⇒ Y = 4.66 ⇒⇒ unacceptable
X = 7 ⇒⇒⇒ Y = 5.44 ⇒⇒ unacceptable
X = 8 ⇒⇒⇒ Y = 6.21 ⇒⇒ unacceptable

X = 9 ⇒⇒⇒ Y = 6.99 ⇒⇒ unacceptable

So, The is no value of Y to achieve ⇒⇒ XY * 8 = YYY

================================================

I think the problem is as following:

Given that XY8 = YYY ⇒⇒⇒ Where X and Y are digits
So, X is equal to one of the digits from 1 to 9
and Y is one of the digits from 1 to 9
This can be solved as following
YYY = 100Y + 10Y + Y = Y(100+10+1) = 111Y
XY8 = 100X + 10Y + 8
∴ 100X + 10Y + 8 = 111Y
∴ 100x + 8 = 101Y
∴ Y = (100X + 8)/101
substitute with X = 1 to 9
X = 1 ⇒⇒⇒ Y = 1.07 ⇒⇒ unacceptable

X = 2 ⇒⇒⇒ Y = 2.06 ⇒⇒ unacceptable
X = 3 ⇒⇒⇒ Y = 3.05 ⇒⇒ unacceptable
X = 4 ⇒⇒⇒ Y = 4.04 ⇒⇒ unacceptable
X = 5 ⇒⇒⇒ Y = 5.03 ⇒⇒ unacceptable
X = 6 ⇒⇒⇒ Y = 6.02 ⇒⇒ unacceptable
X = 7 ⇒⇒⇒ Y = 7.01 ⇒⇒ unacceptable
X = 8 ⇒⇒⇒ Y = 8 ⇒⇒⇒ integer ⇒⇒ the correct answer

X = 9 ⇒⇒⇒ Y =8.99 ⇒⇒ unacceptable

So, The value of Y = 8

8 0

3 years ago

The estimated value of the integral from 0 to 2 of x cubed dx , using the trapezoidal rule with 4 trapezoids is

bulgar [2K]

The integral is approximated by the sum,

$\displaystyle\int_0^2f(x)\,\mathrm dx\approx\sum_{n=0}^4\frac12\times\frac{f(x_n)+f(x_{n+1})}2=\frac14\sum_{n=0}^3(f(x_n)+f(x_{n+1}))$

where $f(x)=x^3$ and $x_n=\dfrac12n$ , giving you

$\displaystyle\frac14\sum_{n=0}^3\bigg(\left(\frac n2\right)^3+\left(\frac{n+1}2\right)^3\bigg)$
$\displaystyle\frac1{32}\sum_{n=0}^3(n^3+(n+1)^3)$
$\displaystyle\frac1{32}\sum_{n=0}^3(2n^3+3n^2+3n+1)$

Faulhaber's formulas make short work of computing the sum. You have

$\displaystyle\sum_{n=0}^k1=k+1$
$\displaystyle\sum_{n=0}^kn=\frac{k(k+1)}2$
$\displaystyle\sum_{n=0}^kn^2=\frac{k(k+1)(2k+1)}6$
$\displaystyle\sum_{n=0}^kn^3=\frac{k^2(k+1)^2}4$

which gives

$\displaystyle\frac1{16}\sum_{n=0}^3n^3+\frac3{32}\sum_{n=0}^3n^2+\frac3{32}\sum_{n=0}^3n+\frac1{32}\sum_{n=0}^31$
$\displaystyle\frac{36}{16}+\frac{42}{32}+\frac{18}{32}+\frac4{32}$
$\implies\displaystyle\int_0^2x^3\,\mathrm dx\approx\frac{17}4=4.25$

4 0

3 years ago