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Verizon [17]
3 years ago
15

Calculate the mass percentage of Na2SO4 in a solution containing 10.9 g Na2SO4 in 482 g water.

Chemistry
2 answers:
mina [271]3 years ago
6 0

Answer:

The mass % of Na2SO4 in this solution is 2.21 %

Explanation:

Step 1: Data given

Mass of Na2SO4 = 10.9 grams

Mass of water = 482 grams

Step 2: Total mass

Total mass = mass Na2SO4 + mass H2O

Total mass = 10.9 grams + 482 grams = 492.9 grams

Step 3: Calculate the mass percentage

Mass % = (mass Na2SO4 / total mass)*100%

mass % = (10.9 grams / 492.9 grams) *100%

mass % =2.21 %

The mass % of Na2SO4 in this solution is 2.21 %

boyakko [2]3 years ago
3 0

Answer:

The answer to your question is 2.21 %

Explanation:

Data

mass of Na₂SO₄ = 10.9 g

mass of H₂O       = 482 g

Formula

Percent by mass = \frac{mass of solute}{total mass} x 100

Substitution

Percent by mass = \frac{10.9}{10.9 + 482} x 100

Simplification and result

Percent by mass = \frac{10.9}{492.9} x 100

       Percent by mass = 0.022 x 100

       Percent by mass = 2.21

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Answer:

The value of n in the hydrate formula is 5 ,CuSO_4.5H_2O.

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The question is incomplete, the complete question is:

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