We’ll be using the equation:
dG = dH - TdS (replace ‘d’ with triangle)
I’m going to assume 0 degrees Celsius.
At 0 C (273 K):
dG = dH - TdS
dG = (285,400 J) - (273 K)(-137.14 J/K)
dG = 285,400 J + 37,439.2 J
dG = 322,839.2 J or 322.84 kJ
The dG of this reaction is +322.84 kJ. This reaction is not considered spontaneous.
This answer, in this instance, would be D. If the temperature used in the question is not 0 degrees C, replace the temperature that I used for calculation with the Kelvin temperature given in the problem (K = C + 273), and simplify to find the answer.
Answer: c. ΔH˚ is positive and ΔS˚ is positive
Explanation:
According to Gibb's equation:

= Gibbs free energy
= enthalpy change
= entropy change
T = temperature in Kelvin
= +ve, reaction is non spontaneous
= -ve, reaction is spontaneous
= 0, reaction is in equilibrium
Thus for 
Case :
> 
when
both have positive values.


Reaction is spontaneous only at at high temperatures.
Na (sodium) and Rb (rubidium) have the most similar chemical properties. They're both Alkali metals, found in the first column of the periodic table.