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Musya8 [376]
3 years ago
12

A sample of neon occupies a volume of 375 ml at stp. What will be the volume of neon If the pressure is reduced to 90.0 KPA?

Chemistry
2 answers:
Leokris [45]3 years ago
5 0

At STP conditions value of absolute pressure is 101.325 kPa.


From the given data we can determine the new volume of neon using following proportion:


V : V1 = p : p1 


375 : V1 = 101.325 : 90


101 * V1 = 90 * 375


V1 =33750/101 =333ml

abruzzese [7]3 years ago
4 0
Since neon is a noble gas we can easily assume its behaviour to be an ideal gas. In ideal gases pressure is said to be inversely proportional to volume,
at fixed temperature, this is Boyle's law.

Therefore we can use this law to state the following equation
P1V1/T1 = P2V2/T2
in this case temperature is fixed therefore it can be eliminated,
then,
P1V1 = P2V2
standard pressure (P1) is 101 325 Pa
V1 = 375 ml
P2 = 90 000 Pa
substituting these values,
101 325 Pa * 375 ml = 90 000 Pa * V2
                          V2 = 101 325 * 375 / 90 000
                               = 422.18 ml
       After rounding off the final answer is option A - 422 ml
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Answer:

a. 478.69 K

b. 939.43 cm^{3}

c. 19.30 J

d. 64.5J

Explanation:

From the question, we can identify the following;

V_{o} = 785cm^{3} = 0.000785 m^{3}

T_{o} = 400K

P_{o} = 125 Kpa =  125 000 Pa

Using the ideal gas equation,

PV = nRT

where R is the molar gas constant = 8.314 m^{3}⋅Pa⋅K^{-1}⋅mol^{-1}

Thus, n = PV/RT = (125000 × 0.000785)/(8.314 × 400) = 0.03 mol

a. Steam temperature in K

To calculate this, we use the constant pressure process;

q = nΔH

Where q is 83.8J according to the question

Thus;

83.8 = 0.03 × [34980 + 35.5T_{1} - (34980 + 35.5T_{o})]

83.8 = (0.03 × 35.5) (T_{1} - 400K)

83.8 = 1.065 (T_{1}  - 400)

78.69 = (T_{1}  - 400)

T_{1} = 400 + 78.69

T_{1}  = 478.69 K

b. Final cylinder volume

To calculate this, we make use of the Charles' law(Temperature and pressure are directly proportional)

V_{1}/T_{1} = V_{o}/T_{o}

V_{1}  =  V_{o}T_{1}/T_{o}

V_{1}   = (785 × 478.69)/400

V_{1}   = 939.43 cm^{3}

c. Work done by the system

Mathematically, the work done by the system is calculated as follows;

w = P(V_{1}- V_{o}) = 125 KPa ( 939.43 - 785) = 19.30 J

d. Change in internal energy of the steam in J

ΔU = q - w = 83.8 - 19.3 = 64.5J

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2 years ago
1. A crane lifts a 75kg mass a height of 8 m. Calculate the gravitational potential energy
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Answer:

GP.E = 5880 j

Explanation:

Given data:

Mass = 75 kg

height = 8 m

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Solution:

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Formula:

GP.E = mgh

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g = 9.8 m/s²

GP.E = 75 Kg × 9.8 m/s²× 8 m

GP.E = 5880 Kg.m²/s²

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