6.7 grams of lithium chloride will be produced.
<h3><u>Explanation:</u></h3>
Lithium chlorate is LiClO₃ and lithium chloride is LiCl. The reaction is,
2LiClO₃ = 2LiCl +3O₂.
So here, 2 moles of lithium chlorate produces 2 moles of lithium chloride.
Or, one molecule of lithium chlorate will produce one mole of lithium chloride.
Molecular weight of lithium chlorate =
= 90.4.
So, 14.3 grams of lithium chlorate has 0.16 moles of lithium chlorate.
Thereby, moles of lithium chloride produced is 0.16 moles.
Molecular weight of lithium chloride = 
= 42.4 grams.
So weight of lithium chloride produced = 
= 6.7 grams.
Thus, weight of lithium chloride produced will be 6.7 grams.
We have the value of
Total energy produced in the chemical reaction=653 550 KJ
Time needed=142.3min
To calculate the rate of energy transfer, that is the amount of energy produced per minute.
Rate of energy transfer=
=
=4592.76 KJ min⁻¹
So, the rate of energy transfer is 4592.76 KJ min⁻¹.
Mendeleev arranged the elements according to their atomic masses
Answer:
%age Yield = 51.45 %
Solution:
Step 1: Convert Kg into g
68.5 Kg CO = 68500 g CO
8.60 Kg H₂ = 8600 g
Step 2: Find out Limiting reactant;
The Balance Chemical Equation is as follow;
CO + 2 H₂ → CH₃OH
According to Equation,
28 g (1 mol) CO reacts with = 4 g (2 mol) of H₂
So,
68500 g CO will react with = X g of H₂
Solving for X,
X = (68500 g × 4 g) ÷ 28 g
X = 9785 g of H₂
It shows 9785 g H₂ is required to react with 68500 g of CO but we are provided with 8600 g of H₂ which is less than required. Therefore, H₂ is provided in less amount hence, it is a Limiting reagent and will control the yield of products.
Step 3: Calculate Theoretical Yield
According to equation,
4 g (2 mol) H₂ reacts to produce = 32 g (1 mol) Methanol
So,
8600 g H₂ will produce = X g of CH₃OH
Solving for X,
X = (8600 g × 32 g) ÷ 4 g
X = 68800 g of CH₃OH
Step 4: Calculate %age Yield
%age Yield = Actual Yield ÷ Theoretical Yield × 100
Putting Values,
%age Yield = 3.54 × 10⁴ g ÷ 68800 g × 100
%age Yield = 51.45 %
