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Elena-2011 [213]
3 years ago
15

The density of iron is about ___ times greater than water. 6, 2, 8, 10, or 4

Chemistry
1 answer:
Lelechka [254]3 years ago
8 0

Answer: 4 i think

Explanation:

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Why is air humid and weather wet at low pressure belts
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In low-pressure belts, there is an absence of surface winds because winds approaching them rise near their margin. This causes vertical currents. when they pass along the ocean, they suck up a lot of water and get a lot of moisture, thus giving wet and humid weather.
3 0
4 years ago
NASA communicates with the Space Shuttle and International Space Station using Ku-band microwave radio. Suppose NASA transmits a
Tanya [424]

Answer:

A = 0.023 m

Explanation:

The relation between the frequency of a radiation and its wavelength is given by the following expression.

where,

c is the speed of light (it has a constant value of 3.00 x 108 m/s)

A is the wavelength of the radiation v is the frequency of the radiation

In this case, the frequency is 13 GHz = 13 x

10° Hz = 13 x 1o° s-

The wavelength associated with this frequency is:

A = c/v = (3.00 x 10° m/s)/(13 x 10° s-") = 0.023

8 0
3 years ago
A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential
nika2105 [10]

Answer:

3.50*10^-11 mol3 dm-9

Explanation:

A silver rod and a SHE are dipped into a saturated aqueous solution of silver oxalate, Ag2C2O4, at 25°C. The measured potential difference between the rod and the SHE is 0.5812 V, the rod being positive. Calculate the solubility product constant for silver oxalate.

Ag2C2O4 -->  2Ag+  +  C2O4 2-

So Ksp = [Ag+]^2 * [C2O42-]

In 1 L, 2.06*10^-4 mol of silver oxalate dissolve, giving, the same number of mol of oxalate ions, and twice the number of mol (4.12*10^-4) of silver ions.

So Ksp = (4.12*10^-4)^2 * (2.06*10^-4)

= 3.50*10^-11 mol3 dm-9

7 0
3 years ago
Would the size of an item affect whether or not it is flammable?
pochemuha

Answer:

No! It only depends on the chemicals in or on the object.

Explanation:

Hope this helped! :)

5 0
3 years ago
03/08/2020
Tanzania [10]

Explanation:

<em>According</em><em> </em><em>to</em><em> </em><em>your</em><em> </em><em>question</em><em>, </em>

<em>no</em><em>.</em><em> </em><em>a</em><em>.</em><em> </em><em>ans</em><em> </em><em>would</em><em> </em><em>be</em><em> </em><em>like</em><em>;</em><em> </em><em>chemical</em><em> </em><em>formula</em><em> </em><em>is</em><em> </em><em>defined</em><em> </em><em>as</em><em> </em><em>the</em><em> </em><em>an</em><em> </em><em>expression</em><em> </em><em>which</em><em> </em><em>determines</em><em> </em><em>no</em><em>.</em><em> </em><em>and</em><em> </em><em>type</em><em> </em><em>of</em><em> </em><em>molecule</em><em> </em><em>of</em><em> </em><em>a</em><em> </em><em>compound</em><em>. </em>

<em>b</em><em>.</em><em> </em><em>no</em><em>.</em><em> </em><em>ans</em><em>;</em><em> </em><em>it</em><em> </em><em>tells</em><em> </em><em>that</em><em> </em><em>what</em><em> </em><em>type</em><em> </em><em>of</em><em> </em><em>compound</em><em> </em><em>is</em><em> </em><em>formed</em><em> </em><em>with</em><em> </em><em>the</em><em> </em><em>type</em><em> </em><em>and</em><em> </em><em>no</em><em>.</em><em> </em><em>of</em><em> </em><em>atoms</em><em> </em><em>present</em><em> </em><em>in</em><em> </em><em>the</em><em> </em><em>atom</em><em>.</em>

<em>c</em><em>.</em><em> </em><em>no</em><em> </em><em> </em><em>ans</em><em>;</em><em> </em><em>the</em><em> </em><em>formulation</em><em> </em><em>of</em><em> </em><em>h2so4</em><em> </em><em>states</em><em> </em><em>that</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>acid</em><em> </em><em>named</em><em> </em><em>as</em><em> </em><em>hydrochloric</em><em> </em><em>acid</em><em> </em><em>which</em><em> </em><em>is</em><em> </em><em>formed</em><em> </em><em>by</em><em> </em><em>reacting</em><em> </em><em>of</em><em> </em><em>hydrogen</em><em> </em><em>(</em><em>2</em><em> </em><em>atoms</em><em> </em><em>)</em><em> </em><em>,</em><em>sulpher</em><em> </em><em>(</em><em>*</em><em>1</em><em>atom</em><em>)</em><em> </em><em>and</em><em> </em><em>oxygen</em><em>(</em><em>4</em><em>atoms</em><em>)</em><em>.</em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

8 0
3 years ago
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