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juin [17]
3 years ago
9

if the coordinates of point a are (-3, 2) and the coordinates of point b are (7, 6), the x-intercept of

Mathematics
1 answer:
Nezavi [6.7K]3 years ago
8 0
Find the equation of the line

slope=(y2-y1)/(x2-x1)
slope=(6-2)/(7-(-3))=4/10=2/5

slope is 2/5
y=mx+b
y=2/5x+b find b
input a point
6=2/5(7)+b
6=14/5+b
minus 14/5 from both sides
3 and 1/5=b
16/5=b
xintercept is when y=0
0=2/5x+16/5
minus 16/5 from both sides
-16/5=2/5x
times both sides by 5/2 to clear fraction
-8=x

xintercept is -8 or (-8,0)
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Step-by-step explanation:

In the geometric series, there is a constant ratio between each two consecutive numbers

<u>Examples:</u>

5,  10,  20,  40,  80,  ………………………. (×2)

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General term (nth term) of a Geometric series is

<em>a1</em> = <em>a</em>, <em>a2</em> = <em>ar</em>, <em>a3</em> = <em>ar</em>²,  <em>a4</em> = <em>ar</em>³, ..........

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<em>a </em>is the first term

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The sum of the first <em>n</em> terms of a Geometric series is calculated by this rule

Sn=\frac{a(1-r^{n})}{1-r}

Let us solve the question

∵ The geometric series is 64, 32, 16, .......................

∴ <em>a </em>= 64

∴ <em>r </em>= 32 ÷ 64 = 0.5

→ We need to find the sum of the first 9 terms

∴ <em>n</em> = 9

→ Substitute these values on the formula of the sum above

∴ S9=\frac{64(1-0.5^{9})}{1-0.5}

→ use the calculator to find the answer

∴ <em>S</em>9 = 127.75

 ∴ The sum of the first 9 terms in the geometric series is 127.75

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