Find the slope of the line that passes through (-1,6) and (15,6)
1 answer:
You might be interested in
Check the picture below.
in a right-triangle, the cosine of one of the acute angles, is equivalent to the sine of the "other" acute angle, as the example shows in the picture.
and since both acute angles are "complementary angles", namely they add up to 90°, then
sin(58°) = cos(90° - 58°)
in a right-triangle, the cosine of one of the acute angles, is equivalent to the sine of the "other" acute angle, as the example shows in the picture.
and since both acute angles are "complementary angles", namely they add up to 90°, then
sin(58°) = cos(90° - 58°)
