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beks73 [17]
3 years ago
7

if I have a binomial distribution where n equals 8 trials and a probability of success equals 0.40 what is the successes of X is

exactly 2
Mathematics
1 answer:
dlinn [17]3 years ago
5 0
P(success) = 0.4   P(failure) = 0.6

8C2 (0.4)² * (0.6)^6

P(2 success) =0.290
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Alex73 [517]

1 Multiply both sides by

n

−

3.2

n−3.2.

n

+

0.3

=

9

2

(

n

−

3.2

)

n+0.3=

2

9

​

(n−3.2)

2 Simplify

9

2

(

n

−

3.2

)

2

9

​

(n−3.2) to

9

(

n

−

3.2

)

2

2

9(n−3.2)

​

.

n

+

0.3

=

9

(

n

−

3.2

)

2

n+0.3=

2

9(n−3.2)

​

3 Multiply both sides by

2

2.

2

n

+

0.6

=

9

(

n

−

3.2

)

2n+0.6=9(n−3.2)

4 Expand.

2

n

+

0.6

=

9

n

−

28.8

2n+0.6=9n−28.8

5 Subtract

2

n

2n from both sides.

0.6

=

9

n

−

28.8

−

2

n

0.6=9n−28.8−2n

6 Simplify

9

n

−

28.8

−

2

n

9n−28.8−2n to

7

n

−

28.8

7n−28.8.

0.6

=

7

n

−

28.8

0.6=7n−28.8

7 Add

28.8

28.8 to both sides.

0.6

+

28.8

=

7

n

0.6+28.8=7n

8 Simplify

0.6

+

28.8

0.6+28.8 to

29.4

29.4.

29.4

=

7

n

29.4=7n

9 Divide both sides by

7

7.

29.4

7

=

n

7

29.4

​

=n

10 Simplify

29.4

7

7

29.4

​

to

4.2

4.2.

4.2

=

n

4.2=n

11 Switch sides.

n

=

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n=4.2

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