Answer:
THE ANSWER WILL BE...
NOTE : Just substitute the x and y variable with (-6,-60) and you will see I am right.
Example:
-60= 10(-6)
<em><u>Please mark as brainliest</u></em>
Have a great day, be safe and healthy
Thank u
XD
Perhaps the easiest way to find the midpoint between two given points is to average their coordinates: add them up and divide by 2.
A) The midpoint C' of AB is
.. (A +B)/2 = ((0, 0) +(m, n))/2 = ((0 +m)/2, (0 +n)/2) = (m/2, n/2) = C'
The midpoint B' is
.. (A +C)/2 = ((0, 0) +(p, 0))/2 = (p/2, 0) = B'
The midpoint A' is
.. (B +C)/2 = ((m, n) +(p, 0))/2 = ((m+p)/2, n/2) = A'
B) The slope of the line between (x1, y1) and (x2, y2) is given by
.. slope = (y2 -y1)/(x2 -x1)
Using the values for A and A', we have
.. slope = (n/2 -0)/((m+p)/2 -0) = n/(m+p)
C) We know the line goes through A = (0, 0), so we can write the point-slope form of the equation for AA' as
.. y -0 = (n/(m+p))*(x -0)
.. y = n*x/(m+p)
D) To show the point lies on the line, we can substitute its coordinates for x and y and see if we get something that looks true.
.. (x, y) = ((m+p)/3, n/3)
Putting these into our equation, we have
.. n/3 = n*((m+p)/3)/(m+p)
The expression on the right has factors of (m+p) that cancel*, so we end up with
.. n/3 = n/3 . . . . . . . true for any n
_____
* The only constraint is that (m+p) ≠ 0. Since m and p are both in the first quadrant, their sum must be non-zero and this constraint is satisfied.
The purpose of the exercise is to show that all three medians of a triangle intersect in a single point.
That would be called the quotient.
The ways can the jazz band be selected so there are 2 trumpet players, 5 drummers, and 3 saxophonists is given below .
Step-by-step explanation:
Let's first do the math with only the trumpet,drummer and saxophonists player.
There are 4 Trumpet Player. There are 4 choices of trumpet players. Which means for each drummer, there are 4 groups of musicians:
T
1
D1S1
T
1
D2S2
and so on
So if there are 4 groups of musicians for each Trumpet ,12 drummer and there are 7 saxophonists , we get 12 groups.
It would be the product of
4T2, 12D5 and 7S3
That is 6*792*35=166,320
