so your saying the start is 0 N and when he/she hits the ball its inertia is 3 N. if that is so m*v=
.05*3=<u>.15</u>
Answer:
the thickness of the film for destructive interference is 1 cm
Explanation:
We can assume that the radar wave penetrates the layer and is reflected in the inner part of it, giving rise to an interference phenomenon of the two reflected rays, we must be careful that the ray has a phase change when
* the wave passes from the air to the film with a higher refractive index
* the wavelength inside the film changes by the refractive index
λ = λ₀ / n
so the ratio for destructive interference is
2 n t = m λ
t = m λ / 2n
indicate that the wavelength λ = 2 cm, suppose that the interference occurs for m = 1, therefore it is thickness
t = 1 2/2 n
t = 1 / n
where n is the index of refraction of the anti-reflective layer. As they tell us not to take into account the change in wavelength when penetrating the film n = 1
t = 1 cm
So the thickness of the film for destructive interference is 1 cm
Answer:
754.8 m
Explanation:
The centripetal acceleration is given by
where v is the speed of the airplane and r is the radius of the loop.
We can rewrite the speed of the airplane as the ratio between the length of the circumference (
) and the time taken:
Substituting in the formula of the acceleration, we have
Re-arranging the formula and putting the numbers of the problem into it, we can find the radius of the loop, r:
Explanation:
Below is an attachment containing the solution.
Vertical forces:
There is a force of 579N acting upward, and a force of 579N
acting downward.
The vertical forces are balanced ... they add up to zero ...
so there's no vertical acceleration.
Not up, not down.
Horizontal forces:
There is a force of 487N acting to the left, and a force of 632N
acting to the right.
The net horizontal force is
(487-left + 632-right) - (632-right - 487-right) = 145N to the right.
The net force on the car is all to the right.
The car accelerates to the right.
