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Olin [163]
2 years ago
15

Tristan walked for 13 1/4 hours in May and June altogether. In May, he walked 6 4/6 hours. How many hours did he walk in June?

Mathematics
1 answer:
Triss [41]2 years ago
5 0
The equation that you should use to solve this is (13 + 1/4) - (6 + 2/3) = 6 and 7/12
 
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Solve for X (picture included)
Fynjy0 [20]

Answer:

x = 41

Step-by-step explanation:

(2x+20) + (2x-4) = 180 degrees

4x+16 = 180 degrees

4x = 164

x = 41

The two sides are supplementary and add up to 180 degrees.

6 0
3 years ago
A survey revealed that 56% of the students at North Valley high school are involved with in a sports team. The survey also showe
oksano4ka [1.4K]

Answer:

The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344

Step-by-step explanation:

56% of the students are involved in a sport team

56% = 0.56

According to the question, it is stated that 24% of the students at the school that are involved in a sports team also participated in the prom dance.

24% = 0.24

This means that we are going to find 24% of the original 56%, since 24% of them also participated in the prom dance.

The probability that a student who is involved in a sports team also participated in the prom dance = 0.24 * 0.56

The probability that a student who is involved in a sports team also participated in the prom dance = 0.1344

5 0
2 years ago
This is due in an hour please be quick!!​
erma4kov [3.2K]

Answer:

106 m^2

Step-by-step explanation:

First multiply the shaded area:

12 * 10 = 120

Then multiply the white space:

7 * 2 = 14

Then subtract the white space from the shaded area to find the area of only the shaded area.

120 - 14 = 106

Final answer: 106 m^2

I hope this helps!

6 0
2 years ago
Read 2 more answers
48, 32 need help to awnser
Gala2k [10]

Answer:

ca ul plz tell what's the question

4 0
3 years ago
Read 2 more answers
A survey is made to determine the number of households having electric appliances in a certain city. It is found that 75% have r
Mashcka [7]

Answer:

The probability that a household has at least one of these appliances is 0.95

Step-by-step explanation:

Percentage of households having radios P(R) = 75% = 0.75

Percentage of households having electric irons P(I) = 65% = 0.65

Percentage of households having electric toasters P(T) = 55% = 0.55

Percentage of household having iron and radio P(I∩R) = 50% = 0.5

Percentage of household having radios and toasters P(R∩T) = 40% = 0.40

Percentage of household having iron and toasters P(I∩T) = 30% = 0.30

Percentage of household having all three P(I∩R∩T) = 20% = 0.20

Probability of households having at least one of the appliance can be calculated using the rule:

P(at least one of the three) = P(R) +P(I) + P(T) - P(I∩R) - P(R∩T) - P(I∩T) + P(I∩R∩T)

P(at least one of the three)=0.75 + 0.65 + 0.55 - 0.50 - 0.40 - 0.30 + 0.20  P(at least one of the three) = 0.95

The probability that a household has at least one of these appliances is 0.95

3 0
2 years ago
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