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elixir [45]
3 years ago
13

A drawing of a surfboard in a catalog shows its length as 8 4/9 inches. Find the actual length of the surfboard if 1/2 inch leng

th on the drawing corresponds to 3/8 foot of actual length.
Mathematics
1 answer:
jonny [76]3 years ago
6 0
3/8 of a foot = 3/8 x 12/1  or 4  1/2 inches

So our 1/2 inch grows by a factor of 9  because 4 1/2 ÷ 1/2 = 9  Think how many 1/2 dollars are in 4  1/2 dollars.  (Answer is 9)

So our 8 4/9 in the catalog has to grow the same

8  4/9   x 9  = 8  4/9  x 9/1 = 76/9 x 9/1  or 76 inches which is 6 ft 4 inches.
(76 ÷12 = 6 r4)

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Tony was Challenged to a half-court shooting competition. For every half-court shot that he makes, he will earn 20 points. For e
Mkey [24]

Answer:

Tony make 4 half-court shots and misses 16 half-court shots.

Step-by-step explanation:

Given:

Points earned for every successful, half-court shots = 20

Points deducted for missing the shots = 5 or -5

Total number of shots in the game = 20

Final points earned by Tony = 0

According to the question:

Let the number of successful half-court shot be x

And the number of shots missed be 20-x

So,

In terms of points we can re-write it as:

⇒ 20(x)-5(20-x) =0

⇒ 20x-100+5x=0

⇒ 25x-100=0

⇒ 25x-100+100=100

⇒ 25x=100

⇒ \frac{25x}{25} =\frac{100}{25}

⇒ x=\frac{100}{25}

⇒ x=4

Tony make 'x' shots that is 4 and the number of shot he missed is (20-x) =(20-4)=16

6 0
3 years ago
Maya reads 1/8 of a newspaper in 1/20
yuradex [85]
So what are u trying to say here. She read in 1/20 of what, minutes, seconds, or what
5 0
3 years ago
How many liters of a 90% acid solution must be added to 6 liters of a 15% acid solution to obtain a 40% acid solution?
tatiyna

3 liters must be added

4 0
3 years ago
How many elements are in the union of five sets if the sets contain 10,000 elements each, each pair of sets has 1000 common elem
masya89 [10]

Answer:

40951

Step-by-step explanation:

Using the principles of inclusion - Exclusion

Where C(n,r)=n!/(n-r)!r!

Total elements in the five sets including number repetition is given as (10000)×C(5, 1) =10000× 5!/(5-1)!1!=10000×5=50000

Total Number of elements in each pair including number repetition of sets is given as

=(1000) × C(5, 2) =10000

Number of elements in each triple of sets is given as

=(100) × C(5, 3) =1000

Number of elements in every four sets

=(10) × C(5, 4)=50

Number of elements in every one set

(1) × C(5, 5)=1

Therefore total number of unique elements=50000-10000+1000-50+1

=40951

5 0
3 years ago
Mr . Berg bought 5 number puzzles and 3 word puzzles for his students . The puzzles were $7 each . Mr . Berg used a $60 gift car
DaniilM [7]

Answer:

Mr. Berg got $4 in change.

Step-by-step explanation:

5 0
3 years ago
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