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Llana [10]
3 years ago
7

Making a pancake from batter is an example of a _____ change

Physics
2 answers:
GenaCL600 [577]3 years ago
7 0
Making a pancake from batter is an example of a chemical change. 
kondaur [170]3 years ago
3 0

Answer:

Making a pancake from batter is an example of a  chemical  change.

Explanation:

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A spring with a spring constant of 4 N/m is stretched by Sarah's dog until extended by 2 m. How much elastic potential energy is
azamat

Hi there!

Recall the equation for spring potential energy:

PE = \frac{1}{2}kx^2

k = Spring constant (N/m)

x = extension of spring from equilibrium (m)

PE = Potential Energy (J)

Plug in the given values:

PE = \frac{1}{2}(4)(2^2) = \boxed{8 J}

8 0
3 years ago
A soldier throws a grenade horizontally from the top of a cliff. Which of the following curves best describes the path taken by
Natasha_Volkova [10]

Answer:

4. Parabola

Explanation:

The motion of the flight of the grenade is a projectile motion, it's shape is best illustrated using a parabolic diagram.

It's not a circle as the path is not totally round.

It's not an ellipse as the path of motion is not a a completely bounded shape.

Its not a hyperbola as a hyperbola is an open curve with two branches.

Its a parabolic shape because a parabola has just one branch

7 0
4 years ago
What does Newton's third law describe?
Dennis_Churaev [7]
A. Equal and opposite forces

Explanation:
History law states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exert an equal and opposite force on object A
7 0
3 years ago
The horizontal bar rises at a constant rate of three hundred mm/s causing peg P to ride in the quarter circular slot. When coord
SVETLANKA909090 [29]

Answer:

Explanation:

Given

Horizontal bar rises with 300 mm/s

Let us take the horizontal component of P be

P_x=rcos\theta

P_y=rsin\theta

where \thetais angle made by horizontal bar with x axis

Velocity at y=150 mm

150=300sin\theta

thus \theta =30^{\circ}

position ofP_x=rcos\theta =300\cdot cos30=300\times \frac{\sqrt{3}}{2}

P_x=259.80 mm

P=259.80\hat{i}+150\hat{j}

Velocity at this instant

u_x=-rsin\theta =300\times sin30=-150 mm/s

u_y=rcos\theta =300\times cos30=259.80 mm/s

4 0
3 years ago
A 52 kg and a 95 kg skydiver jump from an airplane at an altitude of 4750 m, both falling in the pike position. Assume all value
Scilla [17]

Answer: 52 kg skydiver: 9.09 m/s and 522.55 s

              95 kg skydiver: 12.3 m/s and 386.2 s

Explanation: <u>Drag</u> <u>Force</u> is an opposite force when an object is moving in a fluid.

For skydivers, when falling through the air, the forces acting on it are gravitational and drag forces. At a certain point, drag force equals gravitational force, which is constant on any part of the planet, producing a net force that is zero. Since there is no net force, there is no acceleration and, consequently, velocity is constant. When that happens, the person reached the <u>Terminal</u> <u>Velocity</u>.

Drag Force and Velocity are proportional to the squared speed. So, terminal velocity is given by:

F_{G}=F_{D}

mg=\frac{1}{2}C \rho Av_{T}^{2}

v_{T}=\sqrt{\frac{2mg}{\rho CA} }

where

m is mass in kg

g is acceleration due to gravitational force in m/s²

ρ is density of the fluid in kg/m³

C is drag coefficient

A is area of the object in the fluid in m²

Calculating:

The 52kg skydiver has terminal velocity of:

v_{T}=\sqrt{\frac{2(52)(9.8)}{(1.21)(0.7)(0.14)} }

v_{T}= 9.09

The 95kg skydiver's terminal velocity is

v_{T}=\sqrt{\frac{2(95)(9.8)}{(1.21)(0.7)(0.14)} }

v_{T}= 12.3

The 52 kg and 95kg skydivers' terminal velocity are 9.09m/s and 12.3m/s, respectively.

The time each one will reach the floor will be:

52 kg at 9.09 m/s:

t=\frac{4750}{9.09}

t = 522.5

95 kg at 12.3 m/s:

t=\frac{4750}{12.3}

t = 386.2

The 52 kg and 95kg skydivers' time to reach the floor are 522.5 s and 386.2 s, respectively.

3 0
3 years ago
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