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3 years ago

6

Help me please please help me

1 answer:

andreev551 [17]3 years ago

5 0

Answers:

1. B. Circuit
2. D. Electrons moving around
3. B. Series and parallel
4. C. Parallel
5. C. Series
6. A. One
7. C. If one goes down, they both go down.

Hope this helped!

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Solid state physics uses the. Theory to understand how the large-scale properties of solids result from their atomic scale struc

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Quantum theory

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The scientific foundation in quantum mechanics is quantum theory, which describes the existence and behavior of mass and antimatter at the subatomic particles levels. Quantum theory and quantum theory are often related to as the existence and behavior of matter in the universe at that stage.

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Alicia drew a pentagon with equal side length and equal angles.Then she added red lines of symmetry to her drawing. How many lin

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3 years ago

What needs to be applied in order to change an object's momentum?

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Explanation:

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3 years ago

1. You are designing a new solenoid and experimenting with material for each turn. The particular turn you are working with is a

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Answer:

Explanation:

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3 years ago

A merry-go-round with a a radius of R = 1.99 m and moment of inertia I = 194 kg-m2 is spinning with an initial angular speed of

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Answer:

Part 1)

$L_1 = 185.2 kg m^2/s^2$

Part 2)

$L_2 = 663.07 kg m^2/s^2$

Part 3)

$L = 663.07 kg m^2/s^2$

Part 4)

$\omega = 1.83 rad/s$

Part 5)

$F_c = 453.6 N$

Explanation:

Part a)

Initial angular momentum of the merry go round is given as

$L_1 = I \omega$

here we know that

$I = 194 kg m^2$

$\omega = 1.47 rad/s^2$

now we have

$L_1 = 194 \times 1.47$

$L_1 = 185.2 kg m^2/s^2$

Part b)

Angular momentum of the person is given as

$L = mvR$

so we have

$m = 68 kg$

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R = 1.99 m

so we have

$L_2 = (68)(4.9)(1.99)$

$L_2 = 663.07 kg m^2/s^2$

Part 3)

Angular momentum of the person is always constant with respect to the axis of disc

so it is given as

$L = 663.07 kg m^2/s^2$

Part 4)

By angular momentum conservation of the system we will have

$L_1 + L_2 = (I_1 + I_2)\omega$

$185.2 + 663.07 = (194 + 68(1.99^2))\omega$

$848.27 = 463.28 \omega$

$\omega = 1.83 rad/s$

Part 5)

Force required to hold the person is centripetal force which act towards the center

so we will have

$F_c = m\omega^2 R$

$F_c = 68(1.83^2)(1.99)$

$F_c = 453.6 N$

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3 years ago