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Umnica [9.8K]
3 years ago
10

1. What is the pull that all objects exert on each other?

Physics
1 answer:
Andrei [34K]3 years ago
8 0

Answer:

Im pretty sure 1 is gravity, 2 is force

Explanation:

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Racing greyhounds are capable of rounding corners at very high speeds. A typical greyhound track has turns that are 45 m diamete
Readme [11.4K]

Answer:

In m/s^2:

a=11.3778 m/s^2

In units of g:

a=1.161 g

Explanation:

Since the racing greyhounds are capable of rounding corners at very high speed so we are going use the following formula of acceleration for circular paths.

a=\frac{v^2}{r}

where:

v is the speed

r is the radius

Now,

a=\frac{16^2}{45/2}\\ a=11.3778 m/s^2

In g units:

a=\frac{11.3778\ g}{9.8}\\ a=1.161\ g

7 0
3 years ago
Air pollutants often cause irritation in the _____ <br> system.
erastova [34]
Respiratory system.

Oversimplified Explanation: they enter the lungs, which is part of the respiratory system.
7 0
3 years ago
A baseball diamond is a square (don’t be fooled that it is usually shown rotated by 45°). Each side of the square is 90 feet lon
gayaneshka [121]

A line from second to home creates a right triangle with 45 degree angles.

This makes the diagonal line the side length of the square multiplied by the sqrt(2)

Second to home = 90sqrt(2) = 127.279 feet ( round answer as needed)

8 0
3 years ago
Calculate the kinetic energy of a car of mass 800kg moving at 100 kmph.
valentina_108 [34]

Answer:

KE = 308642.02469136 J

4 0
3 years ago
A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration? B. How man
Ne4ueva [31]

Answer:  

A. α = - 1.047 rad/s²  

B. θ = 14.1 rad  

C. θ = 2.24 rev  

Explanation:  

A.  

We can use the first equation of motion to find the acceleration:

\omega_f = \omega_i + \alpha t  

where,  

ωf = final angular speed = 0 rad/s  

ωi = initial angular speed = (30 rpm)(2π rad/1 rev)(1 min/60 s) = 3.14 rad/s  

t = time = 3 s  

α = angular acceleration = ?  

Therefore,

0\ rad/s = 3.14\ rad/s + \alpha(3\ s)  

<u>α = - 1.047 rad/s²</u>

B.  

We can use the second equation of motion to find the angular distance:

\theta = \omega_it +\frac{1}{2}\alpha t^2\\\theta = (3.14\ rad/s)(3\ s) + \frac{1}{2}(1.04\ rad/s^2)(3)^2  

<u>θ = 14.1 rad</u>

C.  

θ = (14.1 rad)(1 rev/2π rad)  

<u>θ = 2.24 rev</u>

6 0
3 years ago
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