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irga5000 [103]
3 years ago
8

What statement best describes the superposition principle (Physics)

Physics
1 answer:
Alexandra [31]3 years ago
5 0

Answer:

The principle of superposition which is also called superposition property,states that when two or more waves of the same type cross at some point, the resultant displacement at that point is equal to the sum of the displacements due to each individual wave.

Explanation:

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Consider the following statements. A. Heat flows from an object at higher temperature to an object at lower temperature; B. Heat
Monica [59]

Answer:

A. Heat flows from an object at higher temperature to an object at lower temperature

Explanation:

The option A obeys the 2nd law of thermodynamics. The heat will flow from the object at higher temperature to the object at Lower temperature till they reach an equilibrial state.

Heat doesn’t necessarily flow from an object with higher thermal energy to an object with lower thermal energy because an object has a higher thermal energy when it’s mass is more than the other. This makes B wrong.

C is wrong because heat moves from an object with higher temperature to objects with Lower temperature regardless of the state of matter.

8 0
3 years ago
Please please help me please
pantera1 [17]
The answer is B) wavelength
7 0
3 years ago
At 20∘C20 ∘ C, the hole in an aluminum ring is 2.500 cm in diameter. You need to slip this ring over a steel shaft that has a ro
Feliz [49]

Answer:

238.75⁰C .

Explanation:

coefficient of linear thermal expansion of aluminum and steel is  23 x 10⁻⁶ K⁻¹ and 12 x 10⁻⁶ K⁻¹ respectively .

Rise in temperature be Δ t .

Formula for linear expansion due to heat is as follows

l = l₀ ( 1 + α x Δt )

l is expanded length , l₀ is initial length , α is coefficient of linear expansion and  Δt is increase in temperature .

For aluminum

l = 2.5 ( 1 +  23 x 10⁻⁶ Δt )

For steel

l = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

Given ,

2.5 ( 1 +  23 x 10⁻⁶ Δt ) = 2.506 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024 ( 1 + 12 x 10⁻⁶ Δt )

1 +  23 x 10⁻⁶ Δt = 1.0024   + 12.0288 x 10⁻⁶ Δt

10.9712 x 10⁻⁶ Δt = .0024

Δt = 218.75

Initial temperature = 20⁰C

final temperature = 218.75 + 20 = 238.75⁰C .

8 0
3 years ago
An amusement park designer wants his swing to have a centripetal acceleration of 24 m/s2. If the velocity of the swing is 11 m/s
viva [34]

Answer:

<u>radius</u><u> </u><u>is</u><u> </u><u>C</u><u>:</u><u> </u><u>5</u><u>.</u><u>0</u><u> </u><u>m</u>

Explanation:

formular for centripetal acceleration:

a =  \frac{ {V}^{2} }{r}

a is acceleration

V is velocity

r is radius

24 =  \frac{ {11}^{2} }{r}  \\  \\ r =  \frac{ {11}^{2} }{24}  \\  \\ r = 5.0 \: m

5 0
3 years ago
Read 2 more answers
A proton and an alpha particle (q = +2e, m = 4 u) are fired directly toward each other from far away, each with an initial speed
stich3 [128]

Answer:

Distance of closest approach, r=1.91\times 10^{-14}\ m

Explanation:

It is given that,

Charge on proton, q_p=e

Charge on alpha particle, q_a=2e

Mass of proton, m_p=1.67\times 10^{-27}\ kg

Mass of alpha particle, m_a=4m_p=6.68\times 10^{-27}\ kg

The distance of closest approach for two charged particle is given by :

r=\dfrac{k2e^2(m_p+m_a)}{2m_am_pv_p^2}

r=\dfrac{9\times 10^9\times 2(1.6\times 10^{-19})^2(1.67\times 10^{-27}+6.68\times 10^{-27})}{2\times 6.68\times 10^{-27}\times 1.67\times 10^{-27}(0.01\times 3\times 10^8)^2}

r=1.91\times 10^{-14}\ m

So, their distance of closest approach, as measured between their centers 1.91\times 10^{-14}\ m. Hence, this is the required solution.

4 0
3 years ago
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