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3 years ago

If EG=10 amd EF=4, then FG=?

Mathematics

1 answer:

blagie [28]3 years ago

8 0

$HEY THERE!!$

If EG = 10
And EF = 4
then FG = 10-4= 6

HOPE IT HELPED YOU.

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Which of the values is equivalent to 5^–3? A) 1/15 B) 1/125 C) − 15 D) − 125

bazaltina [42]

Answer:

C 1/125

Step-by-step explanation:

5 ^−3

Calculate 5 to the power of −3 and get

1/125

7 0

3 years ago

Denise spent $3.45 on snacks every day for 11 days. What is the amount of money Denise spent

musickatia [10]

Answer:

37.95

Step-by-step explanation:

Because 3.45 x 11 is 37.95.

5 0

3 years ago

Read 2 more answers

Unsure how to do this calculus, the book isn't explaining it well. Thanks

krok68 [10]

One way to capture the domain of integration is with the set

$D = \left\{(x,y) \mid 0 \le x \le 1 \text{ and } -x \le y \le 0\right\}$

Then we can write the double integral as the iterated integral

$\displaystyle \iint_D \cos(y+x) \, dA = \int_0^1 \int_{-x}^0 \cos(y+x) \, dy \, dx$

Compute the integral with respect to $y$ .

$\displaystyle \int_{-x}^0 \cos(y+x) \, dy = \sin(y+x)\bigg|_{y=-x}^{y=0} = \sin(0+x) - \sin(-x+x) = \sin(x)$

Compute the remaining integral.

$\displaystyle \int_0^1 \sin(x) \, dx = -\cos(x) \bigg|_{x=0}^{x=1} = -\cos(1) + \cos(0) = \boxed{1 - \cos(1)}$

We could also swap the order of integration variables by writing

$D = \left\{(x,y) \mid -1 \le y \le 0 \text{ and } -y \le x \le 1\right\}$

and

$\displaystyle \iint_D \cos(y+x) \, dA = \int_{-1}^0 \int_{-y}^1 \cos(y+x) \, dx\, dy$

and this would have led to the same result.

$\displaystyle \int_{-y}^1 \cos(y+x) \, dx = \sin(y+x)\bigg|_{x=-y}^{x=1} = \sin(y+1) - \sin(y-y) = \sin(y+1)$

$\displaystyle \int_{-1}^0 \sin(y+1) \, dy = -\cos(y+1)\bigg|_{y=-1}^{y=0} = -\cos(0+1) + \cos(-1+1) = 1 - \cos(1)$

7 0

1 year ago

Evaluate the expression with the given variable replacements.<br> 2x3 (if x = 3)

MArishka [77]

Answer:

if the expression is 2x^3 then answer is 54

Step-by-step explanation:

2x^3

substitute in x=3

2* (3)^3

= 2*3*3*3

= 2*27

= 54

please give thanks, hit that heart button :) good luck

5 0

3 years ago

One sign lights up every 10 seconds. One sign lights up every 12 seconds. If they have just lit up at the same time, how many se

andrew11 [14]

Answer:

It will take 60 seconds for the signs to light up at the same time again.

Step-by-step explanation:

Given:

One sign lights up every 10 seconds

One sign lights up every 12 seconds

They have just lit up at the same time.

To find in how many seconds will it take for the signs to light up at the same time again.

Solution:

In order to find the time in seconds will it take for the signs to light up at the same time again, we need to find the least common multiple of the the times for which the given signs light up.

The numbers are 10 and 12.

To find the LCM, we will list the multiples of each and check the least common multiple.

The multiples of 10 and 12 are :

$10\rightarrow 10,20,30,40,50,60,70$

$12\rightarrow 12,24,36,48,60$

thus, we can see that 60 is the least common multiple.

Thus, the signs will light up at the same time time after every 60 seconds.

7 0

3 years ago