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3 years ago

Help please thanks ................................

Mathematics

2 answers:

solong [7]3 years ago

8 0

Answer:

<em>The correct option is: D. 10</em>

Step-by-step explanation:

According to the given diagram, the distance from point $Y$ to $\overleftrightarrow{WX}$ is $YZ$ .

In the right triangle $XYZ$ , the given lengths are: $XY=10\sqrt{2},\ \ XZ=10$

Using the Pythagorean theorem, we will get......

$(XZ)^2+(YZ)^2=(XY)^2\\ \\ (10)^2+(YZ)^2=(10\sqrt{2})^2\\ \\ 100+(YZ)^2=200\\ \\ (YZ)^2=200-100\\ \\ (YZ)^2=100\\ \\ YZ=\sqrt{100}=10$

So, the distance from point $Y$ to $\overleftrightarrow{WX}$ is 10.

Stells [14]3 years ago

6 0

Answer:

By the pythagoras theorem

(10√2)^2 = ZY^2 + 10^2

ZY = √(200-100)

= 10 answer

Step-by-step explanation:

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vovangra [49]

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2 years ago

Evaluate the following expressions given x=6 and y=-3

Nana76 [90]

$\purple{5 \times 6 - 4 \times ( - 3)}$

$= 30 + 12$

$\blue{ = \boxed{42}}$

$\purple{ {6}^{2} + \frac{6}{ - 3} }$

$= 36 - 2$

$\blue{ = \boxed{34}}$

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7 0

2 years ago

Mary has a collection of nickels and quarters for a total of $4.90. If she has 42 coins in total, how many of each kind are ther

damaskus [11]

Answer:

14 quarters and 28 nickels

Step-by-step explanation:

System of Equations where x = number of quarters and y = number of nickels

(1) equation with value of each coin

0.25(x)+0.05(y) = 4.90

(2) total number of coins

x + y = 42

Solve system of equations using either substitution or elimination

(elimination multiplying equation 2 by -0.5)

.25(x) + 0.05(y) = 4.90

-0.05(x) - 0.05(y) = 42 * (-0.05)

(3) Resulting equation

.20(x) = 2.8

x = 14

plug x into equation 2

14 + y = 42

y = 28

There are 14 quarters and 28 nickels in Mary's collection.

5 0

3 years ago

Find cos(B) A.) 7/3 B.) 3/7 C.) 3/58 D.) 7/58

Alex Ar [27]

A. 7/3
HOPE IT HELLS U!!!!

7 0

3 years ago

Find the values of X and Y that makes these triangles congruent by the HL theorem

muminat

Answer:

C. x = 3, y = 2

Step-by-step explanation:

If both triangles are congruent by the HL Theorem, then their hypotenuse and a corresponding leg would be equal to each other.

Thus:

x + 3 = 3y (eqn. 1) => equal hypotenuse

Also,

x = y + 1 (eqn. 2) => equal legs

✔️Substitute x = y + 1 into eqn. 1 to find y.

x + 3 = 3y (eqn. 1)

(y + 1) + 3 = 3y

y + 1 + 3 = 3y

y + 4 = 3y

y + 4 - y = 3y - y

4 = 2y

Divide both sides by 2

4/2 = 2y/2

2 = y

y = 2

✔️ Substitute y = 2 into eqn. 2 to find x.

x = y + 1 (eqn. 2)

x = 2 + 1

x = 3

8 0

3 years ago