Answer:
we determine that none of the ordered pair is a solution of 
as none of the ordered pairs satisfy the equation.
Step-by-step explanation:
Considering the equation
- Putting (-5,2) in the equation
∵ L.H.S ≠ R.H.S
FALSE
- Putting (0,-5) in the equation
∵ L.H.S ≠ R.H.S
FALSE
- Putting (5,1) in the equation
∵ L.H.S ≠ R.H.S
FALSE
- Putting (7,5) in the equation
∵ L.H.S ≠ R.H.S
FALSE
From the above calculations, we determine that none of the ordered pair is a solution of as none of the ordered pairs satisfy the equation.
Let no. of pens be x.
Pens : x
Pencils: x+8
Total: 2x+8
Student takes 1 pen and 5 pencils.
Remainder: 2x+8 - 5 -1 = 2x+2
2x+2 = 26
2x= 24
x = 12 (original no. of pens)
x+ 8 = 20 (original no of pencils)
There are 12 pens at first and 20 pencils.
After 1 pen is taken, 11 pens are left.
After 5 pencils are taken, 20-5=15 pencils are left.
The answer would be false
Your answer will be 125 x^6 y^12 z^3
Answer:
4 * (3 + 5)
4 * 8
<u>32</u>
Step-by-step explanation:
