Answer:
Option (4)
Step-by-step explanation:
From the graph attached,
Local minimum → (3, -4)
Global Maximum → (-0.44, -4.3)
Maximum of the function → (1.7, 0.7)
Since, local maximum lies in the interval 2.5 ≤ x ≤ 4
Interval that contains the local minimum will be→ [2.5, 4]
Therefore, Option (4) will be the correct option.
First assumption: you want to use all 12 squares in each rectangle.
Let’s assume the squares are 1 inch on a side (could be foot, or yard, or whatever, but 1 UNIT).
Now, a rectangle has a length and a width. 12 squares an inch on a side have a total area of 12 square inches. So, your rectangle will also be 12 square inches.
To get that, you could have a rectangle of the following dimensions:
1 X 12
2 X 6
3 X 4
That’s it. Three possible rectangles, using all 12 squares per rectangle.
Now, if you DON’T have to use all 12 squares in the rectangle, then you could make 6 rectangles, using 2 squares each, so each rectangle would be 1 X 2.
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Related Questions (More Answers Below)
Okay so whats the question? That is just a statement
In mathematics<span>, a (real) </span>interval<span> is a set of real numbers with the property that any number that lies between two numbers in the set is also included in the set. For example, the set of all numbers x satisfying 0 ≤ x ≤ 1 is an </span>interval<span> which contains 0 and 1, as well as all numbers between them. So this should help you solve your problem.</span>
Y + 12 = y + 10 + 2
y + 12 = y + 12
y - y = 12 - 12
0 = 0
True for all y
hope this helps!
