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nadezda [96]
3 years ago
12

Euclid’s root beer mug is shaped basically like a cylinder that is eight inches tall with a radius of three inches. Aristotle’s

root beer glass is shaped basically like a cone that is 18 inches tall with a diameter of four inches. Which vessel holds the most root beer?

Mathematics
1 answer:
olchik [2.2K]3 years ago
3 0

The Euclid's mug holds the most root beer.

Step-by-step explanation:

Euclid's mug :

Height = 8 inches

Radius = 3 inches

Volume = π(r x r) h

= (3.14) (9) 8

= 226.08 cubic inches

Aristotle's mug:

Height = 18 inches

Diameter = 4 inches

Radius = 2 inches

Volume = (1/3) π(r x r) h

= (1/3) (3.14) (4) 18

= 37.68 cubic inches

The Euclid's mug holds the most root beer.

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What is the area of 7 feet by 4 feet
Studentka2010 [4]

Answer:

28.

Step-by-step explanation:

The method of calculating Area is by multiplying the length and the width, therefore it would be:

7 \times 4 = 28

5 0
3 years ago
Find the partial derivatives of the function w=4r2+6s2+
lyudmila [28]
I'm taking the liberty of editing your function as follows:  <span>w=4r^2+6s^2, where I use " ^ " to indicate exponentiation.

The partial of w with respect to r is 8r.  That with respect to s is 12s.</span>
8 0
3 years ago
Alison is learning how to walk. 50% of the time that she takes a step she falls down. Her older brother wants to design a simula
MissTica

Answer with explanation:

Alison is learning how to walk.50% of times she takes a step she falls down.

Probability of falling down in next step =\frac{50}{100}=\frac{1}{2}

Probability of not falling down in next step =\frac{50}{100}=\frac{1}{2}

From ,the four option given,we have to find the best simulation which her older brother wants to design a simulation to find the probability that she will fall down 5 out of the next 7 times she tries to take step.

While Simulating the Probability of falling down should be =\frac{5}{7}

And , probability of not falling down1-\frac{5}{7}=\frac{2}{7}

→→⇒F=Falling, NF=Non Falling

A) Roll a die letting 1 represent Alison falling and 2-6 represent Alison not falling. Roll the die five times.

P(F)=\frac{1}{6},P(NF)=\frac{5}{6}

Incorrect option,probabilities of falling and non falling does not match with Actual probability of falling and non falling.  

B) Roll a die letting 1 represent Alison falling and 2-6 represent Alison not falling. Roll the die seven times.

P(F)=\frac{1}{6},P(NF)=\frac{5}{6}

Incorrect option,probabilities of falling and non falling does not match with Actual probability of falling and non falling.

C) Let Heads represent Alison falling down and Tails representing Alison not falling down. Flip the coin five times.

P(F)=\frac{1}{2},P(NF)=\frac{1}{2}

Simulation is done only five times , that is coin has been flipped only five times.it must have been flipped seven times.Incorrect option.  

D) Let Heads represent Alison falling down and Tails representing Alison not falling down. Flip the coin seven times.

P(F)=\frac{1}{2},P(NF)=\frac{1}{2}

Simulation is done seven times , that is coin has been flipped seven times.So,she should fall 5 times that is head should appear 5 out of seven times, and tail should appear 2 out of seven times.correct option.

Option D

4 0
4 years ago
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Please help! I will mark brainliest:)
STatiana [176]

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Step-by-step explanation:

x will be the game

y = cost

x - 2 because 2 is the initial

you can test it y = 12 + (0.50)*(3-2)

y = 12 +(0.50)*(1)

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8 0
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If the terminal point of theta is(0,-1) what is tan theta
sesenic [268]

Answer:

I'm pretty sure it's undefined, sorry if this is wrong

Step-by-step explanation:

6 0
3 years ago
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