Answer:
To find the x-intercept, make y equal to zero, and solve for x. To find the y-intercept, make x equal to zero, and solve for y.
Explanation:
<span>y=4x−2</span>
<span>
</span>
X-Intercept
<span>0=4x−2</span>
<span>
</span>
Add 2 to both sides of the equation.
<span>2=4x</span>
<span>
</span>
Divide both sides by 4.
<span><span>2/4</span>=x</span>
<span>
</span>
Simplify.
<span><span>1/2</span>=x</span>
<span>
</span>
Switch sides.
<span>x=<span>1/2</span></span>
<span><span>
</span></span>
Y-Intercept
<span>y=4<span>(0)</span>−2</span>
<span>y=−2</span>
a. Answer: D: (∞, ∞)
R: (-∞, ∞)
<u>Step-by-step explanation:</u>
Theoretical domain is the domain of the equation (without an understanding of what the x-variable represents).
Theoretical range is the range of the equation given the domain.
c(p) = 25p
There are no restrictions on the p so the theoretical domain is All Real Numbers.
Multiplying 25 by All Real Numbers results in the range being All Real Numbers.
a) D: (∞, ∞)
R: (-∞, ∞)
*********************************************************************************
b. Answer: D: (0, 200)
R: (0, 5000)
<u>Step-by-step explanation:</u>
Practical domain is the domain of the equation WITH an understanding of what the x-variable represents.
Practical range is the range of the equation given the practical values of the domain.
The problem states that p represents the number of cups. Since we can't have a negative amount of cups, p ≥ 0. The problem also states that Bonnie will purchase a maximum of 200 cups. So, 0 ≤ p ≤ 200
The range is 25p → (25)0 ≤ (25)p ≤ (25)200
→ 0 ≤ 25p ≤ 5000
b) D: (0, 200)
R: (0, 5000)
Answer:
inverse relationship
Step-by-step explanation:
This is inverse becuase as masss increases acceleration decreaes
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Can i please get an image and i will be glad to help :)
Answer:
5 cm
Step-by-step explanation:
We khow that the altitude of this triangle is 1cm shorter than the base
- Let H be our altitude and B our base and A the area of the triangle
- A= (B*H)/2 ⇒ 15=(B*H)/2
- H is 1cm shorter than B ⇒ B=H+1
- H*(H+1)/2=15 ⇒ H*(H+1)=30⇒ H²+H=30⇒H²+H-30+0
that's a quadratic equation . Let's calculate the dicriminant .
Let Δ be the dicriminant
- a=1
- b=1
- c= -30
- Δ=b²-4*a*c = 1²-4*1*(-30)=1+4*30=121≥0
- Δ≥0⇔ that we have two solutions x and y
- x= (-1-
)/2= (-1-11)/2= -6 - y= (-1+
)/2= 10/2 = 5
We have a negative value and a positive one
The altitude is a distance so it can't be negative
H= 5cm