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Naddik [55]
3 years ago
7

Choose the abbreviation of the postulate or theorem that supports the conclusion that WAS NOT. Given: W = N, S = T, WA = NO.

Mathematics
2 answers:
Anastaziya [24]3 years ago
8 0

Answer:

AAS I just answered this question and I got it right.

Elenna [48]3 years ago
8 0

Answer:

AAS

Step-by-step explanation:

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Please answer this question now
Rashid [163]

Answer:

54

Step-by-step explanation:

To solve problems like this, always recall the "Two-Tangent theorem", which states that two tangents of a circle are congruent if they meet at an external point outside the circle.

The perimeter of the given triangle = IK + KM + MI

IK = IJ + JK = 13

KM = KL + LM = ?

MI = MN + NI ?

Let's find the length of each tangents.

NI = IJ = 5 (tangents from external point I)

JK = IK - IJ = 13 - 5 = 8

JK = KL = 8 (Tangents from external point K)

LM = MN = 14 (Tangents from external point M)

Thus,

IK = IJ + JK = 5 + 8 = 13

KM = KL + LM = 8 + 14 = 22

MI = MN + NI = 14 + 5 = 19

Perimeter = IK + KM + MI = 13 + 22 + 19 = 54

4 0
3 years ago
¿Alguien sabe como realizarlo?
sashaice [31]
Hola! Intente resolverlo pero solo hice la primera por mi tiempo ahorita mismo y era:
f(0)=1
Toda la ecuación

7 0
2 years ago
this triangular prism has a length of 20 centimeters, an end base of 6 centimeters and an end height of 8 centimeters. what is t
pochemuha

Answer:

960

Step-by-step explanation:

LxWxH = v

V = 20x 6 x 8

7 0
3 years ago
PLEASE HELP!! DESPERATE!
avanturin [10]

Answer:

Lenght: 34.51 mm

Area: 1035.33 mm^2

Step-by-step explanation:

let x be the unknown sidelength

tan(41) = 30/x

x = 34.51

multiply by 30 to get area

7 0
3 years ago
Can someone please help me it's worth five points
Brilliant_brown [7]

The formula of a volume of a cone:

V=\dfrac{1}{3}Bh=\dfrac{1}{3}\pi r^2h

We have:

r=12cm,\ h=8cm

Substitute:

V=\dfrac{1}{3}\pi\cdot12^2\cdot8=\dfrac{1}{3}\pi\cdot144\cdot8=\pi\cdot48\cdot8=384\pi\ cm^2\approx384\cdot3.14=1205.76\ cm^3\approx1206\ cm^3

Answer: 1206 cm³

7 0
3 years ago
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