Use f (x)=7 and g (x)=x+5 to evaluate (f+g)(3)=

During summer weekdays, boats arrive at the inlet drawbridge according to Poisson distribution at a rate of 3 per hour. In a 2-h

mrs_skeptik [129]

Answer:

The probability that no boats arrive is $2.48\times 10^{-3}$ .

Step-by-step explanation:

Poisson distribution:

Poisson distribution is a statistical distribution that helps to find out the probability of a certain is likely occur a specified period of time.

$P(X=x)=\frac{e^{-\lambda t}(\lambda t)^x}{x!}$

$\lambda$ = rate.

Given that, Poisson distribution at a rate of 3 per hour.

$\lambda$ = 3

t=2

x=0

The probability that no boats arrive is

$P(X=0)=\frac{e^{-2\times 3}(2\times 3)^0}{0!}$

$=2.48\times 10^{-3}$

6 0

3 years ago

Help plzzzzzzz <3333

STatiana [176]

Answer:

It is $66.50 cheaper to purchase a return trip ticket than it is to purchase 2 one-way tickets.

Step-by-step explanation:

It is asking us how much does 2 one-way tickets costs as opposed to a return trip ticket. First, let's figure out how much does 2 one-way tickets cost.

Equation:

287.75 x 2 = 575.50

2 one-way tickets cost $575.50.

Then, to find the difference, subtract the return trip cost from the two one-way tickets.

Equation: 575.50 - 509.00 = 66.50

The difference between the two is $66.5

Conclusion: It is $66.50 cheaper to purchase a return trip ticket than it is to purchase 2 one-way tickets.

I hope this helps!

8 0

2 years ago

Read 2 more answers

Verify the identity<br><br> cos quantity x plus pi divided by two = -sin x

In-s [12.5K]

Answer:

Identity is verified.

Step-by-step explanation:

We have to verify the identity $cos(x+\frac{\pi }{2}) = (- sinx)$

To prove any identity we always prove one side(either left hand side or right hand side) of the equation equal to the other side.

In this identity we take the left hand side first

$cos(x+\frac{\pi}{2})$

$=cosx\times cos(\pi/2)-sinx\times sin(\pi/2))$ (as we know cos(a+b) = cosa×cosb-sina×sinb)

$= cosx\times0-sinx\times1$

$= 0-sinx$

= - sinx ( Right hand side)

Hence identity is proved.

6 0

3 years ago

This question has four parts. Two football games were played at a stadium on the same day. Part A At the start of the first game

Leviafan [203]

Answer: ok so 66.66% of the seats were filled aka ocupied

Step-by-step explanation:

5 0

2 years ago

Doug, a student in this class, knows how to write programs in JAVA. Everyone who knows how to write programs in JAVA can get a h

In-s [12.5K]

Missing Part of Question

Explain which rules of inference are used in the above

Answer:

Universal instantiation, Modus ponens and Existential generalization

Step-by-step explanation:

Splitting the Statement into two, we have

"Doug knows how to write program is Java"

and

"Doug can get a high paying job"

Represent Doug with x. Then the statements is rewritten as

P(x) = "x knows how to write program is Java"

and

Q(x) = "x can get a high paying job"

In logic, A premise is a statement in an argument that provides reason or support for the conclusion.

So, Statement 1 can be written as

1. P(x) ---- Premise

Then, we have

2. Vx(P(x) --> Q(x)) -- Premise. This mean that P(x) for all values in the domain.

The universal instantiation of (2) leads to

3. P(Doug) --> Q(Doug)

The modus ponens of the above gives

4. Q(Doug)

The existential generalisation from above gives

5. ƎxQ(x)

Which means someone in this class can get a high paying job.

PS:

Universal Instantiation is a valid rule of inference from a truth about each member of a class of individuals to the truth about a particular individual of that class; it is represented by VxP(x).

Existential Generalisation is a valid rule of inference that allows one to move from a specific statement, or one instance, to a quantified generalized statement, or existential proposition.

It is represented as ƎxP(x)

4 0

2 years ago