Answer:
The P-value for this test is P=0.2415.
Step-by-step explanation:
We have to perform an hypothesis testing on the mean of alla account balances.
The claim is that the mean of all account balances is significantly greater than $1,150.
Then, the null and alternative hypothesis are:

The sample size is n=20, with a sample mean is 110 and standard deviation is 125.
We can calculate the t-statistic as:

The degrees of freedom fot this test are:

For this one-tailed test and 19 degrees of freedom, the P-value is:

Answer:
8.03
Step-by-step explanation:
It would be 8.03 because the two in 8.03<u>2</u> makes the three stay the same instead of rounding up.
Answer:
a. The probability is not equal to 1
b. P (A') = 0.70
c. P ( A U B ) = 0.80
d. P ( A' ∩ B' ) = 0.20
Step-by-step explanation:
a. Because these A and B are disjoint
b. since the probability of A is 0.30 then the probability of A compliment is
P(A compliment ) = 1 - P (A)
P(A compliment ) = 1-0.30
P(A compliment ) = 0.70
c. Since event are disjoint then intersection of A and B is 0, so probability of A U B is;
P ( A U B ) = P (A) + P(B) - P(A∩ B)
P ( A U B ) = 0.30 + 0.50 - 0
P ( A U B ) = 0.80
d. The inetrsection of compilments of A and B are:
by using De Morgan's Law we have,
P ( A' ∩ B' ) = P [(A U B )']
P ( A' ∩ B' ) = 1 - P ( A U B )
P ( A' ∩ B' ) = 1 - 0.80
P ( A' ∩ B' ) = 0.20
Answer:
-√2
Step-by-step explanation:
For the typing purpose I replaced θ with n in the calculation

Answer:
a^2 + b^2 = c^2
Step-by-step explanation:
Pythagorean's theorem is found using certain assumptions
Draw a square and make out four aright angles inside of it.
Label each side as 'a' 'b'. 'c'.
Where a is the opposite
b is the adjacent
c is the Hypotenuse.
Find the attached file for more clarity.