Lines and are parallel in the image below. The image will be used to prove that the sum of the measures of the interior angles o
f is 180°.
Which statement would be included in a proof of why ?
Angles F and H are congruent.
Angles A and G are congruent.
Angles A and H are congruent.
Angles E and C are congruent.
Which statement would be included in a proof of why ?
Angles F and H are congruent.
Angles A and G are congruent.
Angles A and H are congruent.
Angles E and C are congruent.
2 answers:
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Hey there!
First, let's multiply each side of the equation by 3 to get rid of the fraction .
9 + 2x =
Next we can multiply each side of the equation by 5 to get rid of the fraction .
45 + 10x = 6
There's your answer!
Hope this helps!
Let
x-------> the width of the rectangular area
y------> the length of the rectangular area
we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2
substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft
see the attached figure
the solution is<span> the shaded area</span>
x-------> the width of the rectangular area
y------> the length of the rectangular area
we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2
substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
the length of the rectangular area is at most 45 ft
see the attached figure
the solution is<span> the shaded area</span>