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VLD [36.1K]
3 years ago
15

There are 18 bicycles. There are more more blue than yellow. There are 2 less yellow than green. How many of each color are ther

e?
Mathematics
1 answer:
nasty-shy [4]3 years ago
5 0
The are 8 blue bicycles, 6 green bicycles, and 4 yellow bicycles and total they equal 18.
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Number 49....I need help
sergiy2304 [10]
Now, keep in mind that, we'll be using 25mile intervals, notice, that at a cost of 200 bucks, it went for 50 miles, now the charges are just for every 25miles only, so, if you drive 30 miles, you pay for 25miles and if you drive for 49 miles, you still only pay for 25 miles, but because 50/25 is 2 intervals, then if you drive for 50 miles, you're paying for 2 intervals of 25miles, not just one.

now, also let's keep in mind that, when the car was driven for 200 miles, that's 200/25 or 8 25mile intervals, so the 25mile charge kicked in 8 times.

\bf \stackrel{cost}{y}=\stackrel{fixed~charge}{F}+\stackrel{25mile~intervals}{m}\quad \stackrel{25mile~charge}{x}\implies y=F+mx\\\\
-------------------------------\\\\
\begin{cases}
200=F+2x\implies 200-2x=\boxed{F}\\
245=F+8x\\
----------\\
245=\boxed{200-2x}+8x
\end{cases}
\\\\\\
45=6x\implies \cfrac{45}{6}=x\implies \cfrac{15}{2}=x\impliedby 
\begin{array}{llll}
\textit{so the 25mile charge is}\\
\textit{7 bucks and 50cents}
\end{array}
\\\\\\


\bf 200=F+2\left( \frac{15}{2} \right)\implies 200=F+15\implies 185=F
\\\\\\
\textit{and the \underline{fixed charge} is 185 bucks then, let's check for 450}
\\\\\\
\boxed{y=185+\frac{15}{2}x}\qquad 
\begin{cases}
450~miles\\\\
\cfrac{450}{25}\implies 18~\textit{\underline{25mile intervals}}\\\\
x=18
\end{cases}
\\\\\\
y=185+\cfrac{15}{2}\cdot 18\implies y=185+135\implies y=320
7 0
3 years ago
¯\_(ツ)_/¯ㄟ( ▔, ▔ )ㄏ○| ̄|_つ﹏⊂
babunello [35]

Answer:

the fourth answer

Step-by-step explanation:

4 0
3 years ago
shari’s class is making team pennants for an upcoming field day.they cut the pennants out of a large sheet of paper in the patte
Svetllana [295]
In this item, it is assumed that since the pattern is cut out of the paper which is usually a rectangle then, the shape of the pattern is also rectangle. The perimeter of the rectangle is,

           P = 2L + 2W

The area is equal to,
              Area = L x W

If we assume that length and width are equal, in order to maximize the space. 
              1600 cm² = L x L

The value of L from the equation is 40 cm. 
8 0
3 years ago
Read 2 more answers
I need some help please
Galina-37 [17]

Answer:

  1. Hexagon
  2. Heptagon

Step-by-step explanation:

The first shape has 6 sides. Hence, it is called a hexagon.

The second shape has 7 sides. Hence, it is called a heptagon.

8 0
2 years ago
Read 2 more answers
In 1998, Cathy's age is equal to the sum of the four digits in the year of her birthday, then how old was Cathy in 1998?
ycow [4]

Answer:

<em>Cathy was born in 1980 and she was 18 years old in 1998</em>

Step-by-step explanation:

<u>Equations</u>

This is a special type of equations where all the unknowns must be integers and limited to a range [0,9] because they are the digits of a number.

Let's say Cathy was born in the year x formed by the ordered digits abcd. A number expressed by its digits can be calculated as

x=1000a+100b+10c+d

In 1998, Cathy's age was

1998-(1000a+100b+10c+d)

And it must be equal to the sum of the four digits

1998-(1000a+100b+10c+d)=a+b+c+d

Rearranging

1998=1001a+101b+11c+2d

We are sure a=1, b=9 because Cathy's age is limited to having been born in the same century and millennium. Thus

1998=1001+909+11c+2d

Operating

88=11c+2d

If now we try some values for c we notice there is only one possible valid combination, since c and d must be integers in the range [0,9]

c=8, d=0

Thus, Cathy was born in 1980 and she was 18 years old in 1998. Note that 1+9+8+0=18

5 0
4 years ago
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