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jok3333 [9.3K]
3 years ago
7

The slope-intercept form of the equation of a line that passes through point (-3, 8) is y=-2/3x+6. What is the point-slope form

of the
equation for this line?

Mathematics
1 answer:
notka56 [123]3 years ago
4 0

Answer:

b. y - 8 = -2/3(x + 3)

Step-by-step explanation:

Well point-slope form takes one point in this case (-3,8) and puts it into the equation.

So this is point slope form,

y -y_{1} = m(x - x_{1} )

The 2 negatives in the -y and -x means you have to change the number to a negative to a positive to a negative.

We plug in (-3,8) to the equation.

y - 8 = m(x + 3)

Well we change the -3 to a 3 because of the negative.

So with the given slope -2/3 we plug that in for m.

y - 8 = -2/3(x + 3)

<em>Thus,</em>

<em>answer choice b is correct.</em>

<em />

<em>Hope this helps :)</em>

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Find the slope: (-4, 3) and (8, -3)
olga2289 [7]

Answer:

-1/2

Step-by-step explanation:

The slope is the change in y over the change in x.

\frac{y_{2} -y_{1} }{x_{2} -x_{1} }

For this question:

\frac{3-(-3)}{-4-8} =\frac{6}{-12} =-\frac{1}{2}

4 0
3 years ago
Read 2 more answers
What is one of the solutions to the following system of equations? y2 x2 = 53 y − x = 5 (−10, −5) (−7, −2) (7, 2) (5, 10).
Aliun [14]

The solution of the system of equation is (-7, -2).

<h2>Given</h2>

The system of the equations;

\rm y^2 + x^2 = 53 \\\\y -x = 5

From equation 1

\rm  y -x=5\\\\y = 5+x

Substitute the value of y in equation 1

\rm y^2+x^2=53\\\\(5+x)^2+x^2=53\\\\25+x^2+10x+x^2=53\\\\2x^2+10x+25-53=0\\\\2 x^2 + 10x - 28 = 0     \\\\Divide \ by \ 2 \ both \ side \ the \ equation\\\\x^2 + 5x - 14 = 0\\\\x^2-7x+2x-14=0\\\\x(x-7) + 2(x-7) =0\\\\(x-7) \ (x+2)=0\\\\x-7=0 \ \ x = 7\\\\x +2 =0 \ \ x=-2

The value of x= 2 is rejected because x = 2 not satisfy the equation.

Substitute 2 for the value of x in equation II

y − x = 5

y – 2 = 5

y = 5 +2

y = 7 (x =2, y =7) … Not included in the options

If x = -7

Substitute the value of x = -7 in the equation

\rm y -x=5\\\\y - (-7)=5\\\\y +7= 5\\\\y = 5-7\\\\y = -2

Hence, the solution of the system of equation is (-7, -2).

To know more about System of Equation click the link given below.

brainly.com/question/1495351

6 0
2 years ago
A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet
gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

h(x)=10+0.1(x^{1.5})

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}

s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx

s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx

s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx

Let 1+0.0225x=t

dx=\frac{1}{0.0225}dt

s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt

s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}

s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}

s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)

s=28.21

Weight of cable=28.21\times 10.4=293.38pound

8 0
3 years ago
Solve using substitution method x-y=11;3x+10y=-6<br> explain please
Tatiana [17]
Ok so for starters you want to choose an equation and solve for a variable.
So, I am going to choose x from the first equation.
Add y to both sides and you get x=11+y
Next, substitute 11+y for x in the other equation so you get...
2(11+y) +10y=-6
Next distribute the 2 throug the 11 and the y
22+2y+10y=-6
12y=-28
y=-28/12
reduce this fraction to make this easier.
y=-7/3
Now plug in why to either of the equations to find x
x-(-7/3)=11
x+7/3=11
x=11-(7/3)
x=(33/3)-(7/3)
x=26/3
so x = 26/3 and y = -7/3
you can also check to see if this is correct by substituting each of these values into the equations.
6 0
3 years ago
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