Answer:
6%
Step-by-step explanation:
I asked this same exact question, no one got the right answer, so I just guessed, and what do you know, I got the answer right! So here you go.
Answer:
C. Test for Goodness-of-fit.
Step-by-step explanation:
C. Test for Goodness-of-fit would be most appropriate for the given situation.
A. Test Of Homogeneity.
The value of q is large when the sample variances differ greatly and is zero when all variances are zero . Sample variances do not differ greatly in the given question.
B. Test for Independence.
The chi square is used to test the hypothesis about the independence of two variables each of which is classified into number of attributes. They are not classified into attributes.
C. Test for Goodness-of-fit.
The chi square test is applicable when the cell probabilities depend upon unknown parameters provided that the unknown parameters are replaced with their estimates and provided that one degree of freedom is deducted for each parameter estimated.
Combine the common factors.
11x + 5 = 180
Subtract 5 from both sides.
11x = 175
Divide 11 from both sides to isolate the x.
x = 15.90909091
Answer:
C or A
Step-by-step explanation:
Answer:
um yea i dont know that
Step-by-step explanation:
