Answer:
The slope of a line that has a y-intercept but no x-intercept will be zero.
Step-by-step explanation:
If the line has no x-intercept, then it never intersects the x-axis, so it must be parallel to the x-axis.
If a line does not have an x-intercept, it means it would never intersect the x-axis.
Thus, it must be parallel to the x-axis, meaning its slope will be zero. It would be just a horizontal line.
For example, y=9 is the line equation that does not have an x-intercept and its slope is zero.
Therefore, the slope of a line that has a y-intercept but no x-intercept will be zero.
Using the law os cosines formula b^2 = a^2 + c^2 - 2*a*c*cos(B)
a = 17, b = 8, c = 16
8^2 = 17^2 + 16^2 - 2*17*16* cos(B)
64 = 289 + 256 - 544 * cos(B)
544*cos(B) = 289 + 256 - 64
544 * cos(B) = 481
cos (B) = 481/544
B = arccos(481/544)
B = 27.8 degrees
X is a element of all real numbers but there is a vertical asymptote at x=o. Mathematically: XeR, x≠0
Answer:
20000000
Step-by-step explanation:
