Well it depends on what the model is but if it's an IRA or whatever so if you make your own model that's easy
For a linear function, the instantaneous rate of change is everywhere equal to the slope. Thus the rate of change of the function h(x)=2x on the interval 2≤x≤4
The rate of change of the function given will equal to its slope, thus;
slope,m=(y-1-y)/(x_1-x)
=(2*4-2*2)/(4-2)
=(8-4)/2
=4/2
=2
the answer is 2
To isolate x, we will first subtract 0.8 from both sides.
0.6x + 0.8 = 1.4
-0.8 -0.8
0.6x = 0.6
Now all we have to do is divide both sides by 0.6, because it is the number besides x.
0.6x/0.6 = 0.6/0.6
x = 1
So you get the answer of x = 1.
The answer is choice D
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Explanation:
We can rule out choice B and choice C which are y = 2.4^x and y = 3.5^x respectively. Why can we eliminate these? Because they are growth functions (the bases are larger than 1). The graph shown is a decay function. It goes downhill as you read it from left to right.
The answer is either choice A or choice D
If we plug in x = -2 into the equations for A and D, we get
y = 0.65^x = 0.65^(-2) = 2.36686
y = 0.32^x = 0.32^(-2) = 9.765625
The result for choice D is much closer to what the graph is showing. The graph appears to have the point (-2,11) on the curve. So that's why choice D is the best answer.
Note: the graph is a bit small and its not entirely clear which points are on this graph other than (0,1). So this is a bit of educated guesswork.
Answer:
30
Step-by-step explanation:
i did the math lol
