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2 years ago

Does anyone know what to do? I’m confused on this please explain step by step

Mathematics

2 answers:

Zina [86]2 years ago

8 0

Answer:

You need to know the conversion between the different units

1 ml is equivalent to 0.001 litres

so therefore, 40,000 litres would be 40 litres

12345 [234]2 years ago

5 0

Answer:

40,000 ml = 40 liters

Step-by-step explanation:

1,000 ml = 1 liter

40,000/1,000 = 40 liters

hope this helps

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Encrypt the word PLACE using an alphabetic Caesar shift cipher with shift 13 ( mapping A and N)

Vladimir [108]

PLACE

P > C

L > Y

A > N

C > P

E > R

CYNPR

6 0

3 years ago

Lakelyn is training for a triathlon she is practising her swiming running and biking skills so far she can swim at a rate of 250

Nezavi [6.7K]

Answer:

The answer to the question is

It would take Lalelyn bout 3 hours to run the 18m miles, and it will take her

$\frac{x}{1.7} +\frac{y}{6} +\frac{z}{12} = t$ and x +y+z =18 where x, y, and z are the distannce covered swimming, running and bikinr respectifully

Step-by-step explanation:

To solve the question, we lisrt out the variables as follows

Swimming speed of Lakelyn = 250 yards every 5 minutes or 250×12 = 3000 yards/hour = 1.7 miles/hr

Running speed of Lakelyn = 6 miles/hour

Biking speed = 12 miles/hour

The duration it will take for Lakelyn to run 18 miles is given by

Timee taken to run 18 miles t = (Distance covered)/ (Speed of Lakelyn))

or t = D/S

Substituting the known values of such as

Running speed of Lakelyn = 6 miles/hour

From which we have the time taken to run 18 miles = 18 miles /(6 miles/hour) = 3 hours

should the 18 miles form part of the triathlon then, we have

$\frac{x}{1.7} +\frac{y}{6} +\frac{z}{12} = t$ and x +y+z =18

Where x, y and z are the distance covered Swimming, Running and Biking respectively

4 0

3 years ago

Read 2 more answers

Craig ran the first part of a race with an average speed of 8 miles per hour and biked the second part of a race with an average

lutik1710 [3]

Let the distance of the first part of the race be x, and that of the second part, 15 - x, then
x/8 + (15 - x)/20 = 1.125
5x + 2(15 - x) = 40 x 1.125
5x + 30 - 2x = 45
3x = 45 - 30 = 15
x = 15/3 = 5

Therefore, the distance of the first part of the race is 5 miles and the time is 5/8 = 0.625 hours or 37.5 minutes
The distance of the second part of the race is 15 - 5 = 10 miles and the time is 1.125 - 0.625 = 0.5 hours or 30 minutes.

4 0

2 years ago

Read 2 more answers

Solve this question in the following photo

katovenus [111]

Answer:

55/43

Step-by-step explanation:

(x/y) = 7/3, (x^2/y^2)=49/9, multiply by 3 above and multiply 2 below, 3x^2/2y^2=147/18. Next apply C&D and you will get (3x^2+2y^2)/(3x^2-2y^2)=(147+18)/(147-18)=165/129=55/43

6 0

2 years ago

There are 125 members in the school

Igoryamba

Answer:

125x + 5,000 > 25,000

5 0

2 years ago