Consider the reaction between iron (III) oxide, Fe2O3 and carbon monoxide, CO.

1 answer:

3 0

Fe2O3 + 3CO --> 2Fe + 3CO2

m(Fe2O3)=213 g
m(CO)=140 g
_______________

n(Fe2O3)=?
m(Fe)=?
n(Fe2O3)=?
n(CO)=?
n(CO2)=?

n(Fe2O3)=m(Fe2O3) / M(Fe2O3)
n(Fe2O3)= 213 g / 159,7 gmol-1 = 1,33 mol

n(CO)= m(CO) / M(CO) n(CO)= 140 g / 28,01 gmol-1 = 4,99 mol

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